1836 United States presidential election in Pennsylvania
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{{Use mdy dates|date=September 2023}}
{{Main|1836 United States presidential election}}
{{Infobox election
| election_name = 1836 United States presidential election in Pennsylvania
| country = Pennsylvania
| type = presidential
| ongoing = no
| previous_election = 1832 United States presidential election in Pennsylvania
| previous_year = 1832
| next_election = 1840 United States presidential election in Pennsylvania
| next_year = 1840
| election_date = November 4, 1836
| image_size = x200px
| image1 = Martin Van Buren circa 1837 crop.jpg
| nominee1 = Martin Van Buren
| party1 = Democratic Party (United States)
| home_state1 = New York
| running_mate1 = Richard Johnson
| electoral_vote1 = 30
| popular_vote1 = 91,457
| percentage1 = 51.18%
| image2 = William Henry Harrison by James Reid Lambdin, 1835 crop.jpg
| nominee2 = William Henry Harrison
| party2 = Whig Party (United States)
| home_state2 = Ohio
| running_mate2 = Francis Granger
| electoral_vote2 = 0
| popular_vote2 = 87,235
| percentage2 = 48.82%
| map_image = Pennsylvania Presidential Election Results 1836.svg
| map_size =
| map_caption = County Results
{{col-begin}}
{{col-2}}
Van Buren
{{legend|#86B6F2|50-60%}}{{legend|#4389E3|60-70%}}{{legend|#1666CB|70-80%}}{{legend|#0645B4|80-90%}}
{{col-2}}
Harrison
{{legend|#FED463|50-60%}}{{legend|#FE9929|60-70%}}{{legend|#ec7014|70–80%}}
{{col-end}}
| title = President
| before_election = Andrew Jackson
| before_party = Democratic Party (United States)
| after_election = Martin Van Buren
| after_party = Democratic Party (United States)
| outgoing_members = OH
| elected_members = AR
}}
{{Elections in Pennsylvania sidebar}}
A presidential election was held in Pennsylvania on November 4, 1836 as part of the 1836 United States presidential election.{{cite news |title=Presidential Elections |url=https://newspapers.library.in.gov/?a=d&d=WM18361112.1.3 |work=Weekly Messenger |date=November 12, 1836}} Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.
Pennsylvania voted for the Democratic candidate, Martin Van Buren, over the Whig candidate, William Henry Harrison. Van Buren won Pennsylvania by a narrow margin of 2.36%. The result would ultimately prove decisive in Van Buren's victory; had Harrison won the state, then Van Buren would not have achieved a majority in the Electoral College, meaning that the election would have been decided in the House of Representatives.
Results
class="wikitable" style="font-size: 95%;" |
colspan="6" | 1836 United States presidential election in Pennsylvania{{cite web|title=1836 Presidential General Election Results - Pennsylvania|url=http://uselectionatlas.org/RESULTS/state.php?year=1836&fips=42&f=1&off=0&elect=0&minper=0|publisher=U.S. Election Atlas|access-date=4 August 2012}} |
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colspan="2" style="width: 15em" |Party
! style="width: 17em" |Candidate ! style="width: 5em" |Votes ! style="width: 7em" |Percentage ! style="width: 5em" |Electoral votes |
style="background-color:#3333FF; width: 3px" |
| style="width: 130px" | Democratic | align="right" | 91,457 | align="right" | 51.18% | align="right" | 30 |
style="background-color:#F0C862; width: 3px" |
| style="width: 130px" | Whig | align="right" | 87,235 | align="right" | 48.82% | align="right" | 0 |
bgcolor="#EEEEEE"
| colspan="3" align="right" | Totals | align="right" | 178,692 | align="right" | 100.0% | align="right" | 30 |
See also
References
{{Reflist}}
{{State Results of the 1836 U.S. presidential election}}
Category:1836 Pennsylvania elections
{{Pennsylvania-election-stub}}