1840 United States presidential election in Indiana

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{{Use mdy dates|date=September 2023}}

{{Main|1840 United States presidential election}}

{{Infobox election

| election_name = 1840 United States presidential election in Indiana

| country = Indiana

| type = presidential

| ongoing = no

| previous_election = 1836 United States presidential election in Indiana

| previous_year = 1836

| next_election = 1844 United States presidential election in Indiana

| next_year = 1844

| election_date = November 2, 1840

| image_size = x200px

| image1 = William Henry Harrison crop.jpg

| nominee1 = William Henry Harrison

| party1 = Whig Party (United States)

| home_state1 = Ohio

| running_mate1 = John Tyler

| electoral_vote1 = 9

| popular_vote1 = 65,302

| percentage1 = 55.86%

| image2 = Martin Van Buren circa 1837 crop.jpg

| nominee2 = Martin Van Buren

| party2 = Democratic Party (United States)

| home_state2 = New York

| running_mate2 = none

| electoral_vote2 = 0

| popular_vote2 = 51,604

| percentage2 = 44.14%

| map_image = Indiana Presidential Election Results 1840.svg

| map_size = 215px

| map_caption = County Results

{{col-begin}}

{{col-3}}

Harrison

{{legend|#FED463|50-60%}}

{{legend|#FE9929|60-70%}}

{{legend|#ec7014|70–80%}}

{{col-3}}

Van Buren

{{legend|#86B6F2|50-60%}}

{{legend|#4389E3|60-70%}}

{{legend|#1666CB|70-80%}}

{{legend|#0646B4|80-90%}}

{{col-3}}

Unknown/No vote

{{legend|#828280}}

{{col-end}}

| title = President

| before_election = Martin Van Buren

| before_party = Democratic Party (United States)

| before_color = FF3333

| after_election = William Henry Harrison

| after_party = Whig Party (United States)

| after_color = FF3333

| outgoing_members = IL

| elected_members = KY

}}

{{ElectionsIN}}

A presidential election was held in Indiana on November 2, 1840 as part of the 1840 United States presidential election.{{cite book |last1=Dubin |first1=Michael J. |title=United States Presidential Elections, 1788–1860: The Official Results by County and State |date=2002 |publisher=McFarland & Co. |location=Jefferson, NC |page=xvi}} Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

Indiana voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Indiana by a margin of 11.72%.

Results

{{Election box runningmate begin | title=1840 United States presidential election in Indiana{{cite web|title=1840 Presidential General Election Results - Indiana|url=http://uselectionatlas.org/RESULTS/state.php?year=1840&f=1&off=0&elect=0&fips=18&submit=Retrieve|publisher=U.S. Election Atlas|access-date=23 December 2013}}}}

{{Election box US candidate with party link|

|party = Whig Party (United States)

|candidate = William Henry Harrison

|homestate = Ohio

|vp_name = John Tyler

|vp_state = Virginia

|votes = 65,302

|percentage = 55.86%

|ev = 9

|evprct = 100.00%

}}

{{Election box US candidate with party link|

|party = Democratic Party (United States)

|candidate = Martin Van Buren

|homestate = New York

|vp_name = Richard M. Johnson

|vp_state = Kentucky

|votes = 51,604

|percentage = 44.14%

|ev = 0

|evprct = 0.00%

}}

{{Election runningmate box total|

|votes = 116,906

|percentage = 100.00%

|ev = 9

|evprct = 100.00%

}}

{{Election box end}}

See also

References

{{reflist}}

{{State Results of the 1840 U.S. presidential election}}

Indiana

1840

Category:1840 Indiana elections

{{Indiana-election-stub}}