1860 United States presidential election in Rhode Island
{{short description|none}}
{{Use mdy dates|date=September 2023}}
{{Main|1860 United States presidential election}}
{{Infobox election
| election_name = 1860 United States presidential election in Rhode Island
| country = Rhode Island
| type = presidential
| ongoing =no
| previous_election = 1856 United States presidential election in Rhode Island
| previous_year = 1856
| next_election = 1864 United States presidential election in Rhode Island
| next_year = 1864
| election_date = November 2, 1860
| image_size = x200px
| image1 = Abraham Lincoln by Alexander Hesler, 1860-restored (cropped).png
| nominee1 = Abraham Lincoln
| party1 = Republican Party (United States)
| alliance1 =
| home_state1 = Illinois
| running_mate1 = Hannibal Hamlin
| electoral_vote1 = 4
| popular_vote1 = 12,244
| percentage1 = 61.37%
| image2 = No image.svg
| nominee2 = {{ubl|Stephen Douglas (Dem)|John C. Breckinridge (SD)|John Bell (CU)}}
| party2 = Fusion
| alliance2 = Democratic
Southern Democratic
Constitutional Union
| colour2 = 1E90FF
| home_state2 = {{ubl|Illinois (Douglas)|Kentucky (Breckinridge)|Tennessee (Bell)}}
| running_mate2 = {{ubl|Herschel V. Johnson (Dem)|Joseph Lane (SD)|Edward Everett (CU)}}
| electoral_vote2 = 0
| popular_vote2 = 7,707
| percentage2 = 38.63%
| map_image = Rhode Island Presidential Election Results 1860.svg
| map_size = 250px
| map_caption = County Results
{{col-begin}}
Lincoln
{{legend|#e27f90|50-60%}}
{{legend|#cc2f4a|60-70%}}
{{col-end}}
| title = President
| before_election = James Buchanan
| before_party = Democratic Party (United States)
| after_election = Abraham Lincoln
| after_party = Republican Party (United States)
}}
{{Elections in Rhode Island sidebar}}
The 1860 United States presidential election in Rhode Island took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose four electors of the Electoral College, who voted for president and vice president.
Rhode Island was won by Republican candidate Abraham Lincoln, who won by a margin of 22.74%.
Results
| class="wikitable" style="font-size: 95%;" |
| colspan="6" | 1860 United States presidential election in Rhode Island{{cite web|title=1860 Presidential General Election Results - Rhode Island|url=http://uselectionatlas.org/RESULTS/state.php?year=1860&fips=44&f=1&off=0&elect=0|publisher=U.S. Election Atlas|access-date=3 August 2012}} |
|---|
| colspan="2" style="width: 15em" |Party
! style="width: 17em" |Candidate ! style="width: 5em" |Votes ! style="width: 7em" |Percentage ! style="width: 5em" |Electoral votes |
| style="background-color:#FF3333; width: 3px" |
| style="width: 130px" | Republican | align="right" | 12,244 | align="right" | 61.37% | align="right" | 4 |
| style="background-color:#C154C1; width: 3px" |
| style="width: 130px" | Fusion | Stephen A. Douglas / John C. Breckinridge / John Bell | align="right" | 7,707 | align="right" | 38.63% | align="right" | 0 |
| bgcolor="#EEEEEE"
| colspan="3" align="right" | Totals | align="right" | 19,951 | align="right" | 100.0% | align="right" | 4 |
= Results By County =
| class="wikitable sortable"
|+1860 United States Presidential Election in Rhode Island (By County){{Cite book |url=https://books.google.com/books?id=Jz4KAQAAMAAJ&pg=PA47 |title=The Tribune Almanac and Political Register |date=1861 |publisher=Tribune Association. |language=en}} ! rowspan="2" |County ! colspan="2" |Abraham Lincoln Republican ! colspan="2" |Stephen A. Douglas/ John C. Breckinridge/ John Bell Fusion ! rowspan="2" |Total Votes cast |
| style="text-align:center;"
!# !% !# !% |
| style="text-align:center;"
|{{party shading/Republican}}|Bristol |{{party shading/Republican}}|667 |{{party shading/Republican}}|59.08% |{{party shading/Fusion}}|462 |{{party shading/Fusion}}|40.92% |{{party shading/Republican}}|1,129 |
| style="text-align:center;"
|{{party shading/Republican}}|Kent |{{party shading/Republican}}|1,246 |{{party shading/Republican}}|65.48% |{{party shading/Fusion}}|657 |{{party shading/Fusion}}|34.52% |{{party shading/Republican}}|1,903 |
| style="text-align:center;"
|{{party shading/Republican}}|Newport |{{party shading/Republican}}|1,610 |{{party shading/Republican}}|64.68% |{{party shading/Fusion}}|879 |{{party shading/Fusion}}|35.32% |{{party shading/Republican}}|2,489 |
| style="text-align:center;"
|{{party shading/Republican}}|Providence |{{party shading/Republican}}|7,202 |{{party shading/Republican}}|59.63% |{{party shading/Fusion}}|4,875 |{{party shading/Fusion}}|40.37% |{{party shading/Republican}}|12,077 |
| style="text-align:center;"
|{{party shading/Republican}}|Washington |{{party shading/Republican}}|1,519 |{{party shading/Republican}}|64.56% |{{party shading/Fusion}}|834 |{{party shading/Fusion}}|35.44% |{{party shading/Republican}}|2,353 |
| style="text-align:center;"
!Total !12,244 !61.37% !7,707 !38.63% !19,951 |
Analysis
With 61.37% of the popular vote, Rhode Island would prove to be Lincoln's fifth strongest state in terms of popular vote percentage in the 1860 election after Vermont, Minnesota, Massachusetts and Maine.{{cite web |title=1860 Presidential Election Statistics |url=https://uselectionatlas.org/RESULTS/stats.php?year=1860&f=1&off=0&elect=0 |access-date=2018-03-05 |publisher=Dave Leip’s Atlas of U.S. Presidential Elections}}
Like New Jersey, New York and Pennsylvania, Rhode Island was one of the four states that had a fusion ticket for the Democrats, which was supported just by the Northern Democrats but also supporters of Southern Democrats and Constitutional Unionists. However, unlike in the other three states the electors on the Democratic ticket in Rhode Island were pledged solely to Douglas, therefore some sources credit the Democratic popular vote to the Northern Democratic nominee.
See also
References
{{Reflist}}
{{State Results of the 1860 U.S. presidential election}}
Category:1860 Rhode Island elections
{{RhodeIsland-election-stub}}