1868 New Jersey gubernatorial election

{{Short description|none}}

{{Use American English|date=January 2025}}

{{Use mdy dates|date=September 2023}}

{{Infobox election

| election_name = 1868 New Jersey gubernatorial election

| country = New Jersey

| type = Presidential

| ongoing = no

| previous_election = 1865 New Jersey gubernatorial election

| previous_year = 1865

| next_election = 1871 New Jersey gubernatorial election

| next_year = 1871

| election_date = November 3, 1868

| image1 = File:Theodore Fitz Randolph (cropped).jpg

| nominee1 = Theodore Fitz Randolph

| party1 = Democratic Party (United States)

| popular_vote1 = 83,955

| percentage1 = 51.42%

| image2 = File:John I. Blair (cropped).jpg

| nominee2 = John Insley Blair

| party2 = Republican Party (United States)

| popular_vote2 = 79,333

| percentage2 = 48.58%

| image_size = x175px

| map_image = 1868 New Jersey gubernatorial election results map by county.svg

| map_size = 280px

| map_caption = County results
Randolph: {{legend0|#7996e2|50–60%}} {{legend0|#6674DE|60–70%}}
Blair: {{legend0|#e27f7f|50-60%}} {{legend0|#d75d5d|60–70%}}

| title = Governor

| before_election = Marcus Lawrence Ward

| before_party = Republican Party (United States)

| after_election = Theodore Fitz Randolph

| after_party = Democratic Party (United States)

}}

{{ElectionsNJ}}

The 1868 New Jersey gubernatorial election was held on November 3, 1868. Democratic nominee Theodore Fitz Randolph defeated Republican nominee John Insley Blair with 51.42% of the vote.