Artin–Tate lemma

In algebra, the Artin–Tate lemma, named after John Tate and his former advisor Emil Artin, states:Eisenbud, David, Commutative Algebra with a View Toward Algebraic Geometry, Graduate Texts in Mathematics, 150, Springer-Verlag, 1995, {{ISBN|0-387-94268-8}}, Exercise 4.32

:Let A be a commutative Noetherian ring and B \sub C commutative algebras over A. If C is of finite type over A and if C is finite over B, then B is of finite type over A.

(Here, "of finite type" means "finitely generated algebra" and "finite" means "finitely generated module".) The lemma was introduced by E. Artin and J. Tate in 1951E Artin, J.T Tate, "A note on finite ring extensions," J. Math. Soc Japan, Volume 3, 1951, pp. 74–77 to give a proof of Hilbert's Nullstellensatz.

The lemma is similar to the Eakin–Nagata theorem, which says: if C is finite over B and C is a Noetherian ring, then B is a Noetherian ring.

Proof

The following proof can be found in Atiyah–MacDonald.M. Atiyah, I.G. Macdonald, Introduction to Commutative Algebra, Addison–Wesley, 1994. {{ISBN|0-201-40751-5}}. Proposition 7.8 Let x_1,\ldots, x_m generate C as an A-algebra and let y_1, \ldots, y_n generate C as a B-module. Then we can write

:x_i = \sum_j b_{ij}y_j \quad \text{and} \quad y_iy_j = \sum_{k}b_{ijk}y_k

with b_{ij},b_{ijk} \in B. Then C is finite over the A-algebra B_0 generated by the b_{ij},b_{ijk}. Using that A and hence B_0 is Noetherian, also B is finite over B_0. Since B_0 is a finitely generated A-algebra, also B is a finitely generated A-algebra.

Noetherian necessary

Without the assumption that A is Noetherian, the statement of the Artin–Tate lemma is no longer true. Indeed, for any non-Noetherian ring A we can define an A-algebra structure on C = A\oplus A by declaring (a,x)(b,y) = (ab,bx+ay). Then for any ideal I \subset A which is not finitely generated, B = A \oplus I \subset C is not of finite type over A, but all conditions as in the lemma are satisfied.

References

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