Berlekamp–Welch algorithm

{{Short description|Error-correcting algorithm}}

The Berlekamp–Welch algorithm, also known as the Welch–Berlekamp algorithm, is named for Elwyn R. Berlekamp and Lloyd R. Welch. This is a decoder algorithm that efficiently corrects errors in Reed–Solomon codes for an RS(n, k), code based on the Reed Solomon original view where a message m_1, \cdots, m_k is used as coefficients of a polynomial F(a_i) or used with Lagrange interpolation to generate the polynomial F(a_i) of degree < k for inputs a_1 , \cdots, a_k and then F(a_i) is applied to a_{k+1}, \cdots , a_n to create an encoded codeword c_1, \cdots , c_n.

The goal of the decoder is to recover the original encoding polynomial F(a_i), using the known inputs a_1, \cdots , a_n and received codeword b_1, \cdots , b_n with possible errors. It also computes an error polynomial E(a_i) where E(a_i) = 0 corresponding to errors in the received codeword.

The key equations

Defining e = number of errors, the key set of n equations is

:b_i E(a_i) = E(a_i) F(a_i)

Where E(ai) = 0 for the e cases when bi ≠ F(ai), and E(ai) ≠ 0 for the n - e non error cases where bi = F(ai) . These equations can't be solved directly, but by defining Q() as the product of E() and F():

:Q(a_i) = E(a_i) F(a_i)

and adding the constraint that the most significant coefficient of E(ai) = ee = 1, the result will lead to a set of equations that can be solved with linear algebra.

:b_i E(a_i) = Q(a_i)

:b_i E(a_i) - Q(a_i) = 0

:b_i(e_0 + e_1 a_i + e_2 a_i^2 + \cdots + e_e a_i^e) -(q_0 + q_1 a_i + q_2 a_i^2 + \cdots + q_q a_i^q) = 0

where q = n - e - 1. Since ee is constrained to be 1, the equations become:

:b_i(e_0 + e_1 a_i + e_2 a_i^2 + \cdots + e_{e-1} a_i^{e-1}) -(q_0 + q_1 a_i + q_2 a_i^2 + \cdots + q_q a_i^q) = - b_i a_i^e

resulting in a set of equations which can be solved using linear algebra, with time complexity O(n^3).

The algorithm begins assuming the maximum number of errors e = ⌊(n-k)/2⌋. If the equations can not be solved (due to redundancy), e is reduced by 1 and the process repeated, until the equations can be solved or e is reduced to 0, indicating no errors. If Q()/E() has remainder = 0, then F() = Q()/E() and the code word values F(ai) are calculated for the locations where E(ai) = 0 to recover the original code word. If the remainder ≠ 0, then an uncorrectable error has been detected.

Example

Consider RS(7,3) (n = 7, k = 3) defined in {{math|GF(7)}} with α = 3 and input values: ai = i-1 : {0,1,2,3,4,5,6}. The message to be systematically encoded is {1,6,3}. Using Lagrange interpolation, F(ai) = 3 x2 + 2 x + 1, and applying F(ai) for a4 = 3 to a7 = 6, results in the code word {1,6,3,6,1,2,2}. Assume errors occur at c2 and c5 resulting in the received code word {1,5,3,6,3,2,2}. Start off with e = 2 and solve the linear equations:

:\begin{bmatrix}

b_1 & b_1 a_1 & -1 & -a_1 & -a_1^2 & -a_1^3 & -a_1^4 \\

b_2 & b_2 a_2 & -1 & -a_2 & -a_2^2 & -a_2^3 & -a_2^4 \\

b_3 & b_3 a_3 & -1 & -a_3 & -a_3^2 & -a_3^3 & -a_3^4 \\

b_4 & b_4 a_4 & -1 & -a_4 & -a_4^2 & -a_4^3 & -a_4^4 \\

b_5 & b_5 a_5 & -1 & -a_5 & -a_5^2 & -a_5^3 & -a_5^4 \\

b_6 & b_6 a_6 & -1 & -a_6 & -a_6^2 & -a_6^3 & -a_6^4 \\

b_7 & b_7 a_7 & -1 & -a_7 & -a_7^2 & -a_7^3 & -a_7^4 \\

\end{bmatrix}

\begin{bmatrix}

e_0 \\ e_1 \\ q0 \\ q1 \\ q2 \\ q3 \\ q4 \\

\end{bmatrix}

=

\begin{bmatrix}

-b_1 a_1^2\\

-b_2 a_2^2\\

-b_3 a_3^2\\

-b_4 a_4^2\\

-b_5 a_5^2\\

-b_6 a_6^2\\

-b_7 a_7^2\\

\end{bmatrix}


:\begin{bmatrix}

1 & 0 & 6 & 0 & 0 & 0 & 0 \\

5 & 5 & 6 & 6 & 6 & 6 & 6 \\

3 & 6 & 6 & 5 & 3 & 6 & 5 \\

6 & 4 & 6 & 4 & 5 & 1 & 3 \\

3 & 5 & 6 & 3 & 5 & 6 & 3 \\

2 & 3 & 6 & 2 & 3 & 1 & 5 \\

2 & 5 & 6 & 1 & 6 & 1 & 6 \\

\end{bmatrix}

\begin{bmatrix}

e_0 \\ e_1 \\ q0 \\ q1 \\ q2 \\ q3 \\ q4 \\

\end{bmatrix}

=

\begin{bmatrix}

0\\

2\\

2\\

2\\

1\\

6\\

5\\

\end{bmatrix}


:\begin{bmatrix}

1 & 0 & 0 & 0 & 0 & 0 & 0 \\

0 & 1 & 0 & 0 & 0 & 0 & 0 \\

0 & 0 & 1 & 0 & 0 & 0 & 0 \\

0 & 0 & 0 & 1 & 0 & 0 & 0 \\

0 & 0 & 0 & 0 & 1 & 0 & 0 \\

0 & 0 & 0 & 0 & 0 & 1 & 0 \\

0 & 0 & 0 & 0 & 0 & 0 & 1 \\

\end{bmatrix}

\begin{bmatrix}

e_0 \\ e_1 \\ q0 \\ q1 \\ q2 \\ q3 \\ q4 \\

\end{bmatrix}

=

\begin{bmatrix}

4\\

2\\

4\\

3\\

3\\

1\\

3\\

\end{bmatrix}

Starting from the bottom of the right matrix, and the constraint e2 = 1:

Q(a_i) = 3 x^4 + 1 x^3 + 3 x^2 + 3x + 4

E(a_i) = 1 x^2 + 2 x + 4

F(a_i) = Q(a_i) / E(a_i) = 3 x^2 + 2 x + 1 with remainder = 0.

E(ai) = 0 at a2 = 1 and a5 = 4

Calculate F(a2 = 1) = 6 and F(a5 = 4) = 1 to produce corrected code word {1,6,3,6,1,2,2}.

See also