Convolution of probability distributions
{{short description|Probability distribution of the sum of random variables}}
The convolution/sum of probability distributions arises in probability theory and statistics as the operation in terms of probability distributions that corresponds to the addition of independent random variables and, by extension, to forming linear combinations of random variables. The operation here is a special case of convolution in the context of probability distributions.
Introduction
The probability distribution of the sum of two or more independent random variables is the convolution of their individual distributions. The term is motivated by the fact that the probability mass function or probability density function of a sum of independent random variables is the convolution of their corresponding probability mass functions or probability density functions respectively. Many well known distributions have simple convolutions: see List of convolutions of probability distributions.
The general formula for the distribution of the sum of two independent integer-valued (and hence discrete) random variables isSusan Holmes (1998). Sums of Random Variables:
Statistics 116. Stanford. https://web.archive.org/web/20210413200454/http://statweb.stanford.edu/~susan/courses/s116/node114.html
:
For independent, continuous random variables with probability density functions (PDF) and cumulative distribution functions (CDF) respectively, we have that the CDF of the sum is:
:
If we start with random variables and , related by , and with no information about their possible independence, then:
:
However, if and are independent, then:
:
and this formula becomes the convolution of probability distributions:
:
Example derivation
There are several ways of deriving formulae for the convolution of probability distributions. Often the manipulation of integrals can be avoided by use of some type of generating function. Such methods can also be useful in deriving properties of the resulting distribution, such as moments, even if an explicit formula for the distribution itself cannot be derived.
One of the straightforward techniques is to use characteristic functions, which always exists and are unique to a given distribution.{{citation needed|date=April 2013}}
= Convolution of Bernoulli distributions =
The convolution of two independent identically distributed Bernoulli random variables is a binomial random variable. That is, in a shorthand notation,
:
To show this let
:
==Using probability mass functions==
As
:
&=\sum_{m\in\mathbb{Z}} \mathbb{P}[X_1=m]\times\mathbb{P}[X_2=n-m] \\
&=\sum_{m\in\mathbb{Z}}\left[\binom{1}{m}p^m\left(1-p\right)^{1-m}\right]\left[\binom{1}{n-m}p^{n-m}\left(1-p\right)^{1-n+m}\right]\\
&=p^n\left(1-p\right)^{2-n}\sum_{m\in\mathbb{Z}}\binom{1}{m}\binom{1}{n-m} \\
&=p^n\left(1-p\right)^{2-n}\left[\binom{1}{0}\binom{1}{n}+\binom{1}{1}\binom{1}{n-1}\right]\\
&=\binom{2}{n}p^n\left(1-p\right)^{2-n}=\mathbb{P}[Z=n]
\end{align}
Here, we used the fact that
== Using characteristic functions ==
The characteristic function of each
:
where t is within some neighborhood of zero.
:
&=\prod_{k=1}^2 \operatorname{E}\left(e^{itX_k}\right)=\prod_{k=1}^2 \left(1-p+pe^{it}\right)\\
&=\left(1-p+pe^{it}\right)^2=\varphi_Z(t)\end{align}
The expectation of the product is the product of the expectations since each
Since
See also
References
{{Reflist}}
- {{cite book | last1=Hogg | first1=Robert V. |authorlink1=Robert V. Hogg | last2=McKean | first2=Joseph W. | last3=Craig | first3=Allen T. | title=Introduction to mathematical statistics | edition=6th | publisher=Prentice Hall | url=http://www.pearsonhighered.com/educator/product/Introduction-to-Mathematical-Statistics/9780130085078.page | location=Upper Saddle River, New Jersey | year=2004 | pages=692 | ISBN=978-0-13-008507-8|MR=467974}}