Homotopical connectivity

{{Distinguish|Homotopic connectivity}}

{{About|the concept in algebraic topology|other connectivity concepts|Connectivity (disambiguation){{!}}Connectivity}}

In algebraic topology, homotopical connectivity is a property describing a topological space based on the dimension of its holes. In general, low homotopical connectivity indicates that the space has at least one low-dimensional hole. The concept of n-connectedness generalizes the concepts of path-connectedness and simple connectedness.

An equivalent definition of homotopical connectivity is based on the homotopy groups of the space. A space is n-connected (or n-simple connected) if its first n homotopy groups are trivial.

Homotopical connectivity is defined for maps, too. A map is n-connected if it is an isomorphism "up to dimension n, in homotopy".

Definition using holes

All definitions below consider a topological space X.

A hole in X is, informally, a thing that prevents some suitably-placed sphere from continuously shrinking to a point.{{Cite Matousek 2007}}, Section 4.3{{Rp|page=78}} Equivalently, it is a sphere that cannot be continuously extended to a ball. Formally,

  • A d-dimensional sphere in X is a continuous function f_d: S^d \to X.
  • A d-dimensional ball in X is a continuous function g_d: B^d \to X.
  • A d-dimensional-boundary hole in X is a d-dimensional sphere that is not nullhomotopic (- cannot be shrunk continuously to a point). Equivalently, it is a d-dimensional sphere that cannot be continuously extended to a (d+1)-dimensional ball. It is sometimes called a (d+1)-dimensional hole (d+1 is the dimension of the "missing ball").
  • X is called n-connected if it contains no holes of boundary-dimension dn.{{Rp|page=78|location=Sec.4.3}}
  • The homotopical connectivity of X, denoted \text{conn}_{\pi}(X), is the largest integer n for which X is n-connected.
  • A slightly different definition of connectivity, which makes some computations simpler, is: the smallest integer d such that X contains a d-dimensional hole. This connectivity parameter is denoted by \eta_{\pi}(X), and it differs from the previous parameter by 2, that is, \eta_{\pi}(X) := \text{conn}_{\pi}(X) + 2.{{Cite journal |last1=Aharoni |first1=Ron |last2=Berger |first2=Eli |date=2006 |title=The intersection of a matroid and a simplicial complex |url=https://www.ams.org/tran/2006-358-11/S0002-9947-06-03833-5/ |journal=Transactions of the American Mathematical Society |language=en |volume=358 |issue=11 |pages=4895–4917 |doi=10.1090/S0002-9947-06-03833-5 |issn=0002-9947|doi-access=free }}

= Examples =

File:Hole_with_1-dimensional_boundary.png

  • A 2-dimensional hole (a hole with a 1-dimensional boundary) is a circle (S1) in X, that cannot be shrunk continuously to a point in X. An example is shown on the figure at the right. The yellow region is the topological space X; it is a pentagon with a triangle removed. The blue circle is a 1-dimensional sphere in X. It cannot be shrunk continuously to a point in X; therefore; X has a 2-dimensional hole. Another example is the punctured plane - the Euclidean plane with a single point removed, \mathbb{R}^2\setminus \{(0,0)\}. To make a 2-dimensional hole in a 3-dimensional ball, make a tunnel through it. In general, a space contains a 1-dimensional-boundary hole if and only if it is not simply-connected. Hence, simply-connected is equivalent to 1-connected. X is 0-connected but not 1-connected, so \text{conn}_{\pi}(X) = 0. The lowest dimension of a hole is 2, so \eta_{\pi}(X) = 2.File:Hole_with_a_2-dimensional_boundary.png
  • A 3-dimensional hole (a hole with a 2-dimensional boundary) is shown on the figure at the right. Here, X is a cube (yellow) with a ball removed (white). The 2-dimensional sphere (blue) cannot be continuously shrunk to a single point. X is simply-connected but not 2-connected, so \text{conn}_{\pi}(X) = 1. The smallest dimension of a hole is 3, so \eta_{\pi}(X) = 3.

File:Hole_with_a_0-dimensional_boundary.png

  • For a 1-dimensional hole (a hole with a 0-dimensional boundary) we need to consider S^0 - the zero-dimensional sphere. What is a zero dimensional sphere? - For every integer d, the sphere S^d is the boundary of the (d+1)-dimensional ball B^{d+1}. So S^0 is the boundary of B^1, which is the segment [0,1]. Therefore, S^0 is the set of two disjoint points {0, 1}. A zero-dimensional sphere in X is just a set of two points in X. If there is such a set, that cannot be continuously shrunk to a single point in X (or continuously extended to a segment in X), this means that there is no path between the two points, that is, X is not path-connected; see the figure at the right. Hence, path-connected is equivalent to 0-connected. X is not 0-connected, so \text{conn}_{\pi}(X) = -1. The lowest dimension of a hole is 1, so \eta_{\pi}(X) = 1.
  • A 0-dimensional hole is a missing 0-dimensional ball. A 0-dimensional ball is a single point; its boundary S^{-1} is an empty set. Therefore, the existence of a 0-dimensional hole is equivalent to the space being empty. Hence, non-empty is equivalent to (−1)-connected. For an empty space X, \text{conn}_{\pi}(X) = -2 and \eta_{\pi}(X) = 0, which is its smallest possible value.
  • A ball has no holes of any dimension. Therefore, its connectivity is infinite: \eta_{\pi}(X) = \text{conn}_{\pi}(X) = \infty.

= Homotopical connectivity of spheres =

In general, for every integer d, \text{conn}_{\pi}(S^d)=d-1 (and \eta_{\pi}(S^d)=d+1){{Rp|page=79|location=Thm.4.3.2}} The proof requires two directions:

  • Proving that \text{conn}_{\pi}(S^d) < d, that is, S^d cannot be continuously shrunk to a single point. This can be proved using the Borsuk–Ulam theorem.
  • Proving that \text{conn}_{\pi}(S^d) \geq d-1, that is, that is, every continuous map S^k \to S^d for k < d can be continuously shrunk to a single point.

Definition using groups

A space X is called n-connected, for n ≥ 0, if it is non-empty, and all its homotopy groups of order dn are the trivial group: \pi_d(X) \cong 0, \quad -1 \leq d \leq n, where \pi_i(X) denotes the i-th homotopy group and 0 denotes the trivial group.{{Cite web |title=n-connected space in nLab |url=https://ncatlab.org/nlab/show/n-connected+space |access-date=2017-09-18 |website=ncatlab.org}} The two definitions are equivalent. The requirement for an n-connected space consists of requirements for all dn:

  • The requirement for d=−1 means that X should be nonempty.
  • The requirement for d=0 means that X should be path-connected.
  • The requirement for any d ≥ 1 means that X contains no holes of boundary dimension d. That is, every d-dimensional sphere in X is homotopic to a constant map. Therefore, the d-th homotopy group of X is trivial. The opposite is also true: If X has a hole with a d-dimensional boundary, then there is a d-dimensional sphere that is not homotopic to a constant map, so the d-th homotopy group of X is not trivial. In short, X has a hole with a d-dimensional boundary, if-and-only-if \pi_d(X) \not \cong 0.The homotopical connectivity of X is the largest integer n for which X is n-connected.{{cite arXiv |last1=Frick |first1=Florian |last2=Soberón |first2=Pablo |date=2020-05-11 |title=The topological Tverberg problem beyond prime powers |class=math.CO |eprint=2005.05251 }}

The requirements of being non-empty and path-connected can be interpreted as (−1)-connected and 0-connected, respectively, which is useful in defining 0-connected and 1-connected maps, as below. The 0th homotopy set can be defined as:

:\pi_0(X, *) := \left[\left(S^0, *\right), \left(X, *\right)\right].

This is only a pointed set, not a group, unless X is itself a topological group; the distinguished point is the class of the trivial map, sending S0 to the base point of X. Using this set, a space is 0-connected if and only if the 0th homotopy set is the one-point set. The definition of homotopy groups and this homotopy set require that X be pointed (have a chosen base point), which cannot be done if X is empty.

A topological space X is path-connected if and only if its 0th homotopy group vanishes identically, as path-connectedness implies that any two points x1 and x2 in X can be connected with a continuous path which starts in x1 and ends in x2, which is equivalent to the assertion that every mapping from S0 (a discrete set of two points) to X can be deformed continuously to a constant map. With this definition, we can define X to be n-connected if and only if

:\pi_i(X) \simeq 0, \quad 0 \leq i \leq n.

=Examples=

  • A space X is (−1)-connected if and only if it is non-empty.
  • A space X is 0-connected if and only if it is non-empty and path-connected.
  • A space is 1-connected if and only if it is simply connected.
  • An n-sphere is (n − 1)-connected.

''n''-connected map

The corresponding relative notion to the absolute notion of an n-connected space is an n-connected map, which is defined as a map whose homotopy fiber Ff is an (n − 1)-connected space. In terms of homotopy groups, it means that a map f\colon X \to Y is n-connected if and only if:

  • \pi_i(f)\colon \pi_i(X) \mathrel{\overset{\sim}{\to}} \pi_i(Y) is an isomorphism for i < n, and
  • \pi_n(f)\colon \pi_n(X) \twoheadrightarrow \pi_n(Y) is a surjection.

The last condition is frequently confusing; it is because the vanishing of the (n − 1)-st homotopy group of the homotopy fiber Ff corresponds to a surjection on the nth homotopy groups in the exact sequence

:\pi_n(X) \mathrel{\overset{\pi_n(f)}{\to}} \pi_n(Y) \to \pi_{n-1}(Ff).

If the group on the right \pi_{n-1}(Ff) vanishes, then the map on the left is a surjection.

Low-dimensional examples:

  • A connected map (0-connected map) is one that is onto path components (0th homotopy group); this corresponds to the homotopy fiber being non-empty.
  • A simply connected map (1-connected map) is one that is an isomorphism on path components (0th homotopy group) and onto the fundamental group (1st homotopy group).

n-connectivity for spaces can in turn be defined in terms of n-connectivity of maps: a space X with basepoint x0 is an n-connected space if and only if the inclusion of the basepoint x_0 \hookrightarrow X is an n-connected map. The single point set is contractible, so all its homotopy groups vanish, and thus "isomorphism below n and onto at n" corresponds to the first n homotopy groups of X vanishing.

=Interpretation=

This is instructive for a subset:

an n-connected inclusion A \hookrightarrow X is one such that, up to dimension n − 1, homotopies in the larger space X can be homotoped into homotopies in the subset A.

For example, for an inclusion map A \hookrightarrow X to be 1-connected, it must be:

  • onto \pi_0(X),
  • one-to-one on \pi_0(A) \to \pi_0(X), and
  • onto \pi_1(X).

One-to-one on \pi_0(A) \to \pi_0(X) means that if there is a path connecting two points a, b \in A by passing through X, there is a path in A connecting them, while onto \pi_1(X) means that in fact a path in X is homotopic to a path in A.

In other words, a function which is an isomorphism on \pi_{n-1}(A) \to \pi_{n-1}(X) only implies that any elements of \pi_{n-1}(A) that are homotopic in X are abstractly homotopic in A – the homotopy in A may be unrelated to the homotopy in X – while being n-connected (so also onto \pi_n(X)) means that (up to dimension n − 1) homotopies in X can be pushed into homotopies in A.

This gives a more concrete explanation for the utility of the definition of n-connectedness: for example, a space where the inclusion of the k-skeleton is n-connected (for n > k) – such as the inclusion of a point in the n-sphere – has the property that any cells in dimensions between k and n do not affect the lower-dimensional homotopy types.

Lower bounds

Many topological proofs require lower bounds on the homotopical connectivity. There are several "recipes" for proving such lower bounds.

= Homology{{Anchor|homology}} =

The Hurewicz theorem relates the homotopical connectivity \text{conn}_{\pi}(X) to the homological connectivity, denoted by \text{conn}_H(X). This is useful for computing homotopical connectivity, since the homological groups can be computed more easily.

Suppose first that X is simply-connected, that is, \text{conn}_{\pi}(X)\geq 1. Let n := \text{conn}_{\pi}(X) + 1\geq 2; so \pi_i(X)= 0 for all i, and \pi_n(X)\neq 0. Hurewicz theorem{{citation |last=Hatcher |first=Allen |title=Algebraic Topology |year=2001 |publisher=Cambridge University Press |isbn=978-0-521-79160-1 |author-link=Allen Hatcher}}{{Rp|page=366|location=Thm.4.32}} says that, in this case, \tilde{H_i}(X)= 0 for all i, and \tilde{H_n}(X) is isomorphic to \pi_n(X), so \tilde{H_n}(X)\neq 0 too. Therefore:\text{conn}_H(X) = \text{conn}_{\pi}(X).If X is not simply-connected (\text{conn}_{\pi}(X)\leq 0), then\text{conn}_H(X)\geq \text{conn}_{\pi}(X)still holds. When \text{conn}_{\pi}(X)\leq-1 this is trivial. When \text{conn}_{\pi}(X)=0 (so X is path-connected but not simply-connected), one should prove that \tilde{H_0}(X)= 0.{{Clarify|date=May 2022}}

The inequality may be strict: there are spaces in which \text{conn}_{\pi}(X)=0 but \text{conn}_H(X)=\infty.See example 2.38 in Hatcher's book. See also [https://math.stackexchange.com/a/4441587/29780 this answer].

By definition, the k-th homology group of a simplicial complex depends only on the simplices of dimension at most k+1 (see simplicial homology). Therefore, the above theorem implies that a simplicial complex K is k-connected if and only if its (k+1)-dimensional skeleton (the subset of K containing only simplices of dimension at most k+1) is k-connected.{{Rp|page=80|location=Prop.4.4.2}}

= Join =

Let K and L be non-empty cell complexes. Their join is commonly denoted by K * L . Then:''{{Rp|page=81|location=Prop.4.4.3}}

\text{conn}_{\pi}(K*L) \geq \text{conn}_{\pi}(K)+\text{conn}_{\pi}(L)+2.

The identity is simpler with the eta notation:

\eta_{\pi}(K*L) \geq \eta_{\pi}(K)+\eta_{\pi}(L).

As an example, let K = L = S^0 = a set of two disconnected points. There is a 1-dimensional hole between the points, so the eta is 1. The join K * L is a square, which is homeomorphic to a circle, so its eta is 2. The join of this square with a third copy of K is a octahedron, which is homeomorphic to S^2 , and its eta is 3. In general, the join of n copies of S^0 is homeomorphic to S^{n-1} and its eta is n.

The general proof is based on a similar formula for the homological connectivity.

= Nerve =

Let K1,...,Kn be abstract simplicial complexes, and denote their union by K.

Denote the nerve complex of {K1, ... , Kn} (the abstract complex recording the intersection pattern of the Ki) by N.

If, for each nonempty J\subset I, the intersection \bigcap_{i\in J} U_i is either empty or (k−|J|+1)-connected, then for every jk, the j-th homotopy group of N is isomorphic to the j-th homotopy group of K.

In particular, N is k-connected if-and-only-if K is k-connected.{{Cite journal |last=Björner |first=Anders |authorlink1=Anders Björner |date=2003-04-01 |title=Nerves, fibers and homotopy groups |journal=Journal of Combinatorial Theory | series=Series A |language=en |volume=102 |issue=1 |pages=88–93 |doi=10.1016/S0097-3165(03)00015-3 |doi-access=free |issn=0097-3165}}{{Rp|location=Thm.6}}

Homotopy principle

In geometric topology, cases when the inclusion of a geometrically-defined space, such as the space of immersions M \to N, into a more general topological space, such as the space of all continuous maps between two associated spaces X(M) \to X(N), are n-connected are said to satisfy a homotopy principle or "h-principle". There are a number of powerful general techniques for proving h-principles.

See also

References