Kiepert conics

In triangle geometry, the Kiepert conics are two special conics associated with the reference triangle. One of them is a hyperbola, called the Kiepert hyperbola and the other is a parabola, called the Kiepert parabola. The Kiepert conics are defined as follows:

:If the three triangles $A^\prime BC$ , $AB^\prime C$ and $ABC^\prime$ , constructed on the sides of a triangle $ABC$ as bases, are similar, isosceles and similarly situated, then the triangles $ABC$ and $A^\prime B^\prime C^\prime$ are in perspective. As the base angle of the isosceles triangles varies between $-\pi/2$ and $\pi/2$ , the locus of the center of perspectivity of the triangles $ABC$ and $A^\prime B^\prime C^\prime$ is a hyperbola called the Kiepert hyperbola and the envelope of their axis of perspectivity is a parabola called the Kiepert parabola.

It has been proved that the Kiepert hyperbola is the hyperbola passing through the vertices, the centroid and the orthocenter of the reference triangle and the Kiepert parabola is the parabola inscribed in the reference triangle having the Euler line as directrix and the triangle center X₁₁₀ as focus.{{cite web |last1=Kimberling, C. |title=X(110)=Focus of Kiepert Parabola |url=http://faculty.evansville.edu/ck6/encyclopedia/ETC.html#X110. |website=Encyclopedia of Triangle Centers |access-date=4 February 2022}} The following quote from a paper by R. H. Eddy and R. Fritsch is enough testimony to establish the importance of the Kiepert conics in the study of triangle geometry:{{cite journal |last1=Eddy |first1=R. H. |last2=Fritsch |first2=R. |title=The Conics of Ludwig Kiepert: A Comprehensive Lesson in the Geometry of the Triangle |journal=Math. Mag. |date=1994 |volume=67 |issue=3 |pages=188–205|doi=10.1080/0025570X.1994.11996212 }}

:"If a visitor from Mars desired to learn the geometry of the triangle but could stay in the earth's relatively dense atmosphere only long enough for a single lesson, earthling mathematicians would, no doubt, be hard-pressed to meet this request. In this paper, we believe that we have an optimum solution to the problem. The Kiepert conics ...."

Kiepert hyperbola

The Kiepert hyperbola was discovered by Ludvig Kiepert while investigating the solution of the following problem proposed by Emile Lemoine in 1868: "Construct a triangle, given the peaks of the equilateral triangles constructed on the sides." A solution to the problem was published by Ludvig Kiepert in 1869 and the solution contained a remark which effectively stated the locus definition of the Kiepert hyperbola alluded to earlier.

=Basic facts=

Let $a, b, c$ be the side lengths and $A,B,C$ the vertex angles of the reference triangle $ABC$ .

==Equation==

The equation of the Kiepert hyperbola in barycentric coordinates $x:y:z$ is

: $\frac{b^2-c^2}{x}+\frac{c^2-a^2}{y}+\frac{a^2-b^2}{z}=0.$

==Center, asymptotes==

The centre of the Kiepert hyperbola is the triangle center X(115). The barycentric coordinates of the center are

: $(b^2-c^2)^2 : (c^2-a^2)^2 : (a^2-b^2)^2$ .

The asymptotes of the Kiepert hyperbola are the Simson lines of the intersections of the Brocard axis with the circumcircle.
The Kiepert hyperbola is a rectangular hyperbola and hence its eccentricity is $\sqrt{2}$ .

=Properties=

The center of the Kiepert hyperbola lies on the nine-point circle. The center is the midpoint of the line segment joining the isogonic centers of triangle $ABC$ which are the triangle centers X(13) and X(14) in the Encyclopedia of Triangle Centers.
The image of the Kiepert hyperbola under the isogonal transformation is the Brocard axis of triangle $ABC$ which is the line joining the symmedian point and the circumcenter.
Let $P$ be a point in the plane of a nonequilateral triangle $ABC$ and let $p$ be the trilinear polar of $P$ with respect to $ABC$ . The locus of the points $P$ such that $p$ is perpendicular to the Euler line of $ABC$ is the Kiepert hyperbola.

Kiepert parabola

The Kiepert parabola was first studied in 1888 by a German mathematics teacher Augustus Artzt in a "school program".{{cite journal |last1=Sharp, J. |title=Artzt parabolas of a triangle |journal=The Mathematical Gazette |date=2015 |volume=99 |issue=546 |pages=444–463 |doi=10.1017/mag.2015.81|s2cid=123814409 }}

=Basic facts=

The equation of the Kiepert parabola in barycentric coordinates $x:y:z$ is

:: $f^2x^2+g^2y^2+h^2z^2 - 2fgxy - 2ghyz - 2 hfzx=0$
where
$f=(b^2-c^2)/a, g=(c^2-a^2)/b, h=(a^2-b^2)/c$ .

The focus of the Kiepert parabola is the triangle center X(110). The barycentric coordinates of the focus are

:: $a^2/(b^2-c^2) : b^2/(c^2-a^2) : c^2/(a^2-b^2)$

The directrix of the Kiepert parabola is the Euler line of triangle $ABC$ .

Images

KiepertHyperbola01.png|Kiepert hyperbola showing the center of perspectivity of triangles ABC and A'B'C'

KiepertHyperbola02.png|Kiepert hyperbola showing the orthocenter, the incenter and the perpendicular asymptotes

KiepertParabola.png|Kiepert parabola of triangle ABC. The figure also shows a member (line LMN) of the family of lines whose envelope is the Kiepert parabola.

KiepertParabola01.png|Kiepert parabola showing the focus and the directrix

External links

{{cite web |last1=Weisstein, Eric W. |title=Kiepert Hyperbola |url=https://mathworld.wolfram.com/KiepertHyperbola.html |website=MathWorld--A Wolfram Web Resource. |access-date=5 February 2022}}
{{cite web |last1=Weisstein, Eric W. |title=Kiepert Parabola |url=https://mathworld.wolfram.com/KiepertParabola.html |website=MathWorld--A Wolfram Web Resource. |access-date=5 February 2022}}

References

Category:Triangle geometry

Kiepert conics

Kiepert hyperbola

=Basic facts=

==Equation==

==Center, asymptotes==

=Properties=

Kiepert parabola

=Basic facts=

Images

See also

External links

References