Lifting theory

{{Short description|Notion in measure theory}}

In mathematics, lifting theory was first introduced by John von Neumann in a pioneering paper from 1931, in which he answered a question raised by Alfréd Haar.

{{Cite journal|year=1931|first=John|last=von Neumann|authorlink=John von Neumann|title=Algebraische Repräsentanten der Funktionen "bis auf eine Menge vom Maße Null"| url=http://www.degruyter.com/view/j/crll.1931.1931.issue-165/crll.1931.165.109/crll.1931.165.109.xml|journal=Journal für die reine und angewandte Mathematik|language=de|volume=1931|issue=165|pages=109–115|doi=10.1515/crll.1931.165.109|mr=1581278|url-access=subscription}} The theory was further developed by Dorothy Maharam (1958){{Cite journal|last=Maharam|first=Dorothy|authorlink=Dorothy Maharam|year=1958|title=On a theorem of von Neumann|url=https://www.ams.org/jourcgi/jour-getitem?pii=S0002-9939-1958-0105479-6|journal=Proceedings of the American Mathematical Society|volume=9|issue=6|pages=987–994|doi=10.2307/2033342|jstor=2033342|mr=0105479|doi-access=free}} and by Alexandra Ionescu Tulcea and Cassius Ionescu Tulcea (1961).{{Cite journal|last1= Ionescu Tulcea|first1=Alexandra|author1-link=Alexandra Bellow|last2=Ionescu Tulcea|first2=Cassius|author2-link=Cassius Ionescu-Tulcea|year=1961|title=On the lifting property. I.|journal=Journal of Mathematical Analysis and Applications|volume=3|issue=3|pages=537–546|doi=10.1016/0022-247X(61)90075-0|mr=0150256|doi-access=free}} Lifting theory was motivated to a large extent by its striking applications. Its development up to 1969 was described in a monograph of the Ionescu Tulceas.{{cite book|last1= Ionescu Tulcea|first1=Alexandra|author1-link=Alexandra Bellow|last2=Ionescu Tulcea|first2=Cassius|author2-link=Cassius Ionescu-Tulcea|year=1969|title=Topics in the theory of lifting|series=Ergebnisse der Mathematik und ihrer Grenzgebiete|volume=48|publisher=Springer-Verlag|location= New York|oclc=851370324|mr=0276438}} Lifting theory continued to develop since then, yielding new results and applications.

Definitions

A lifting on a measure space (X, \Sigma, \mu) is a linear and multiplicative operator

T : L^\infty(X, \Sigma, \mu) \to \mathcal{L}^\infty(X, \Sigma, \mu)

which is a right inverse of the quotient map

\begin{cases}

\mathcal L^\infty(X,\Sigma,\mu) \to L^\infty(X,\Sigma,\mu) \\

f \mapsto [f]

\end{cases}

where \mathcal{L}^\infty(X,\Sigma,\mu) is the seminormed Lp space of measurable functions and L^\infty(X, \Sigma, \mu) is its usual normed quotient. In other words, a lifting picks from every equivalence class [f] of bounded measurable functions modulo negligible functions a representative— which is henceforth written T([f]) or T[f] or simply Tf — in such a way that T[1] = 1 and for all p \in X and all r, s \in \Reals,

T(r[f]+s[g])(p) = rT[f](p) + sT[g](p),

T([f]\times[g])(p) = T[f](p) \times T[g](p).

Liftings are used to produce disintegrations of measures, for instance conditional probability distributions given continuous random variables, and fibrations of Lebesgue measure on the level sets of a function.

Existence of liftings

Theorem. Suppose (X, \Sigma, \mu) is complete.A subset N \subseteq X is locally negligible if it intersects every integrable set in \Sigma in a subset of a negligible set of \Sigma. (X, \Sigma, \mu) is complete if every locally negligible set is negligible and belongs to \Sigma. Then (X, \Sigma, \mu) admits a lifting if and only if there exists a collection of mutually disjoint integrable sets in \Sigma whose union is X.

In particular, if (X, \Sigma, \mu) is the completion of a σ-finitei.e., there exists a countable collection of integrable sets – sets of finite measure in \Sigma – that covers the underlying set X. measure or of an inner regular Borel measure on a locally compact space, then (X, \Sigma, \mu) admits a lifting.

The proof consists in extending a lifting to ever larger sub-σ-algebras, applying Doob's martingale convergence theorem if one encounters a countable chain in the process.

Strong liftings

Suppose (X, \Sigma, \mu) is complete and X is equipped with a completely regular Hausdorff topology \tau \subseteq \Sigma such that the union of any collection of negligible open sets is again negligible – this is the case if (X, \Sigma, \mu) is σ-finite or comes from a Radon measure. Then the support of \mu, \operatorname{Supp}(\mu), can be defined as the complement of the largest negligible open subset, and the collection C_b(X, \tau) of bounded continuous functions belongs to \mathcal L^\infty(X, \Sigma, \mu).

A strong lifting for (X, \Sigma, \mu) is a lifting

T : L^\infty(X, \Sigma, \mu) \to \mathcal{L}^\infty(X, \Sigma, \mu)

such that T\varphi = \varphi on \operatorname{Supp}(\mu) for all \varphi in C_b(X, \tau). This is the same as requiring thatU, \operatorname{Supp}(\mu) are identified with their indicator functions. T U \geq (U \cap \operatorname{Supp}(\mu)) for all open sets U in \tau.

Theorem. If (\Sigma, \mu) is σ-finite and complete and \tau has a countable basis then (X, \Sigma, \mu) admits a strong lifting.

Proof. Let T_0 be a lifting for (X, \Sigma, \mu) and U_1, U_2, \ldots a countable basis for \tau. For any point p in the negligible set

N := \bigcup\nolimits_n \left\{p \in \operatorname{Supp}(\mu) : (T_0U_n)(p) < U_n(p)\right\}

let T_p be any characterA character on a unital algebra is a multiplicative linear functional with values in the coefficient field that maps the unit to 1. on L^\infty(X, \Sigma, \mu) that extends the character \phi \mapsto \phi(p) of C_b(X, \tau). Then for p in X and [f] in L^\infty(X, \Sigma, \mu) define:

(T[f])(p):= \begin{cases} (T_0[f])(p)& p\notin N\\

T_p[f]& p\in N.

\end{cases}

T is the desired strong lifting.

Application: disintegration of a measure

Suppose (X, \Sigma, \mu) and (Y, \Phi, \nu) are σ-finite measure spaces (\mu, \nu positive) and \pi : X \to Y is a measurable map. A disintegration of \mu along \pi with respect to \nu is a slew Y \ni y \mapsto \lambda_y of positive σ-additive measures on (\Sigma, \mu) such that

  1. \lambda_y is carried by the fiber \pi^{-1}(\{y\}) of \pi over y, i.e. \{y\} \in \Phi and \lambda_y\left((X\setminus \pi^{-1}(\{y\})\right) = 0 for almost all y \in Y
  2. for every \mu-integrable function f,\int_X f(p)\;\mu(dp)= \int_Y \left(\int_{\pi^{-1}(\{y\})} f(p)\,\lambda_y(dp)\right) \nu(dy) \qquad (*) in the sense that, for \nu-almost all y in Y, f is \lambda_y-integrable, the function y \mapsto \int_{\pi^{-1}(\{y\})} f(p)\,\lambda_y(dp) is \nu-integrable, and the displayed equality (*) holds.

Disintegrations exist in various circumstances, the proofs varying but almost all using strong liftings. Here is a rather general result. Its short proof gives the general flavor.

Theorem. Suppose X is a Polish spaceA separable space is Polish if its topology comes from a complete metric. In the present situation it would be sufficient to require that X is Suslin, that is, is the continuous Hausdorff image of a Polish space. and Y a separable Hausdorff space, both equipped with their Borel σ-algebras. Let \mu be a σ-finite Borel measure on X and \pi : X \to Y a \Sigma, \Phi-measurable map. Then there exists a σ-finite Borel measure \nu on Y and a disintegration (*).

If \mu is finite, \nu can be taken to be the pushforwardThe pushforward \pi_* \mu of \mu under \pi, also called the image of \mu under \pi and denoted \pi(\mu), is the measure \nu on \Phi defined by \nu(A) := \mu\left(\pi^{-1}(A)\right) for A in \Phi. \pi_* \mu, and then the \lambda_y are probabilities.

Proof. Because of the polish nature of X there is a sequence of compact subsets of X that are mutually disjoint, whose union has negligible complement, and on which \pi is continuous. This observation reduces the problem to the case that both X and Y are compact and \pi is continuous, and \nu = \pi_* \mu. Complete \Phi under \nu and fix a strong lifting T for (Y, \Phi, \nu). Given a bounded \mu-measurable function f, let \lfloor f\rfloor denote its conditional expectation under \pi, that is, the Radon-Nikodym derivative off \mu is the measure that has density f with respect to \mu \pi_*(f \mu) with respect to \pi_* \mu. Then set, for every y in Y, \lambda_y(f) := T(\lfloor f\rfloor)(y). To show that this defines a disintegration is a matter of bookkeeping and a suitable Fubini theorem. To see how the strongness of the lifting enters, note that

\lambda_y(f \cdot \varphi \circ \pi) = \varphi(y) \lambda_y(f) \qquad \forall y\in Y, \varphi \in C_b(Y), f \in L^\infty(X, \Sigma, \mu)

and take the infimum over all positive \varphi in C_b(Y) with \varphi(y) = 1; it becomes apparent that the support of \lambda_y lies in the fiber over y.

References

{{reflist}}

{{Measure theory}}

Category:Measure theory