Narayana polynomials

Narayana polynomials are a class of polynomials whose coefficients are the Narayana numbers. The Narayana numbers and Narayana polynomials are named after the Canadian mathematician T. V. Narayana (1930–1987). They appear in several combinatorial problems.{{cite journal |last1=D. G. Rogers |title=Rhyming schemes: Crossings and coverings |journal=Discrete Mathematics |date=1981 |volume=33 |pages=67–77 |doi=10.1016/0012-365X(81)90259-4 |url=https://core.ac.uk/download/pdf/82236401.pdf |access-date=2 December 2023}}{{cite book |last1=R.P. Stanley |title=Enumerative Combinatorics, Vol. 2 |date=1999 |publisher=Cambridge University Press}}{{cite journal |last1=Rodica Simian and Daniel Ullman |title=On the structure of the lattice of noncrossing partitions |journal=Discrete Mathematics |date=1991 |volume=98 |issue=3 |pages=193–206 |doi=10.1016/0012-365X(91)90376-D |url=https://core.ac.uk/download/pdf/82065542.pdf |access-date=2 December 2023}}

Definitions

For a positive integer n and for an integer k\geq0, the Narayana number N(n,k) is defined by

: N(n,k) = \frac{1}{n}{n \choose k}{n\choose k-1}.

The number N(0,k) is defined as 1 for k=0 and as 0 for k\ne0.

For a nonnegative integer n , the n-th Narayana polynomial N_n(z) is defined by

:N_n(z) = \sum_{k=0}^n N(n,k)z^k.

The associated Narayana polynomial \mathcal N_n(z) is defined as the reciprocal polynomial of N_n(z):

:\mathcal N_n(z)=z^nN_n\left(\tfrac{1}{z}\right).

Examples

The first few Narayana polynomials are

:N_0(z)=1

:N_1(z)=z

:N_2(z)=z^2+z

:N_3(z)=z^3+3z^2+z

:N_4(z)=z^4+6z^3+6z^2+z

:N_5(z)=z^5+10z^4+20z^3+10z^2+z

Properties

A few of the properties of the Narayana polynomials and the associated Narayana polynomials are collected below. Further information on the properties of these polynomials are available in the references cited.

= Alternative form of the Narayana polynomials =

The Narayana polynomials can be expressed in the following alternative form:{{cite arXiv |last1=Ricky X. F. Chen and Christian M. Reidys |title=Narayana polynomials and some generalizations |date=2014 |class=math.CO |eprint=1411.2530 }}

  • N_n(z)= \sum_{k=0}^n \frac{1}{n+1}{n+1 \choose k}{2n-k \choose n}(z-1)^k

= Special values =

  • N_n(1) is the n-th Catalan number C_n=\frac{1}{n+1}{2n \choose n} . The first few Catalan numbers are 1, 1, 2, 5, 14, 42, 132, 429, \ldots. {{OEIS|id=A000108}}.{{cite arXiv |last1=Toufik Mansour, Yidong Sun |title=Identities involving Narayana polynomials and Catalan numbers |date=2008 |class=math.CO |eprint=0805.1274 }}
  • N_n(2) is the n-th large Schröder number. This is the number of plane trees having n edges with leaves colored by one of two colors. The first few Schröder numbers are 1, 2, 6, 22, 90, 394, 1806, 8558, \ldots. {{OEIS|id=A006318}}.
  • For integers n\ge 0, let d_n denote the number of underdiagonal paths from (0,0) to (n,n) in a n\times n grid having step set S = \{(k, 0) : k \in \mathbb N^+\} \cup \{(0, k) : k \in \mathbb N^+\}. Then d_n = \mathcal N(4).{{cite journal |last1=Curtis Coker |title=Enumerating a class oflattice paths |journal=Discrete Mathematics |date=2003 |volume=271 |issue=1–3 |pages=13–28 |doi=10.1016/S0012-365X(03)00037-2 |url=https://core.ac.uk/download/pdf/82292598.pdf |access-date=1 December 2023}}

= Recurrence relations =

  • For n \ge 3, \mathcal N_n(z) satisfies the following nonlinear recurrence relation:

:\mathcal N_n(z) = (1+z)N_{n-1}(z) + z \sum_{k=1}^{n-2}\mathcal N_k(z)\mathcal N_{n-k-1}(z).

  • For n\ge 3, \mathcal N_n(z) satisfies the following second order linear recurrence relation:

:(n+1)\mathcal N_n(z) = (2n-1)(1+z)\mathcal N_{n-1}(z) - (n-2)(z-1)^2\mathcal N_{n-2}(z) with \mathcal N_1(z)=1 and \mathcal N_2(z)=1+z.

= Generating function =

The ordinary generating function the Narayana polynomials is given by

: \sum_{n=0}^{\infty} N_n(z)t^n = \frac{1+t-t z -\sqrt{1 - 2(1+z) t + (1-z)^2 t^2 }}{2 t}.

= Integral representation =

The n-th degree Legendre polynomial P_n(x) is given by

: P_n(x) = 2^{-n}\sum_{k=0}^{\left\lfloor \frac{n}{2}\right\rfloor } (-1)^k {n-k \choose k}{2n-2k \choose n-k}x^{n-2k}

Then, for n > 0, the Narayana polynomial N_n(z) can be expressed in the following form:

  • N_n(z)=(z-1)^{n+1}\int_0^{\frac{z}{z-1}} P_n(2x-1)\,dx.

See also

References

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Category: Polynomials