Spherical sector#Volume

{{Short description|Intersection of a sphere and cone emanating from its center}}

File:Kugel-sektor.png

File:Spherical sector.png

In geometry, a spherical sector,{{MathWorld | id=SphericalSector | title=Spherical sector}} also known as a spherical cone,{{MathWorld |id=SphericalCone |title=Spherical cone}} is a portion of a sphere or of a ball defined by a conical boundary with apex at the center of the sphere. It can be described as the union of a spherical cap and the cone formed by the center of the sphere and the base of the cap. It is the three-dimensional analogue of the sector of a circle.

Volume

If the radius of the sphere is denoted by {{mvar|r}} and the height of the cap by {{mvar|h}}, the volume of the spherical sector is

V = \frac{2\pi r^2 h}{3}\,.

This may also be written as

V = \frac{2\pi r^3}{3} (1-\cos\varphi)\,,

where {{mvar|φ}} is half the cone aperture angle, i.e., {{mvar|φ}} is the angle between the rim of the cap and the axis direction to the middle of the cap as seen from the sphere center. The limiting case is for {{mvar|φ}} approaching 180 degrees, which then describes a complete sphere.

The height, {{mvar|h}} is given by

h = r (1-\cos\varphi)\,.

The volume {{mvar|V}} of the sector is related to the area {{mvar|A}} of the cap by:

V = \frac{rA}{3}\,.

Area

The curved surface area of the spherical sector (on the surface of the sphere, excluding the cone surface) is

A = 2\pi rh\,.

It is also

A = \Omega r^2

where {{math|Ω}} is the solid angle of the spherical sector in steradians, the SI unit of solid angle. One steradian is defined as the solid angle subtended by a cap area of {{math|1=A = r2}}.

Derivation

{{further|double integral|triple integral}}

The volume can be calculated by integrating the differential volume element

dV = \rho^2 \sin \phi \, d\rho \, d\phi \, d\theta

over the volume of the spherical sector,

V = \int_0^{2\pi} \int_0^\varphi\int_0^r\rho^2\sin\phi \, d\rho \, d\phi \, d\theta = \int_0^{2\pi} d\theta \int_0^\varphi \sin\phi \, d\phi \int_0^r \rho^2 d\rho = \frac{2\pi r^3}{3} (1-\cos\varphi) \, ,

where the integrals have been separated, because the integrand can be separated into a product of functions each with one dummy variable.

The area can be similarly calculated by integrating the differential spherical area element

dA = r^2 \sin\phi \, d\phi \, d\theta

over the spherical sector, giving

A = \int_0^{2\pi} \int_0^\varphi r^2 \sin\phi \, d\phi \, d\theta = r^2 \int_0^{2\pi} d\theta \int_0^\varphi \sin\phi \, d\phi = 2\pi r^2(1-\cos\varphi) \, ,

where {{mvar|φ}} is inclination (or elevation) and {{mvar|θ}} is azimuth (right). Notice {{math|r}} is a constant. Again, the integrals can be separated.

See also

References

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Category:Spherical geometry

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