Talk:Banach–Alaoglu theorem
{{WikiProject banner shell|class=Start|1=
{{WikiProject Mathematics|importance=mid}}
}}
This showed up in Wikipedia:Deletion_log_archive/June_2003 where it
seems someone had unsuccessfully started to put in a proof. I hope this
is more acceptable, even if it is a bare sketch. --
AndrewKepert 08:36, 5 Apr 2004 (UTC)
Why is it so complicated!!!!!!!!! I'm copying the first lines (that are clear) from the intro and put it as a section — Preceding unsigned comment added by Noix07 (talk • contribs) 15:05, 12 December 2013 (UTC)
Sequencially compact
All the applications of the Banach-Alaoglu theorem I know make use of sequencially compactness. Is this a consequence of compactness in this case (or for certain spaces)?--Trigamma 18:41, 17 January 2007 (UTC)
Consequences Section
It says there
The corresponding result for p=1 is not true, as L1(μ) is not reflexive. (*)
however, this does not follow from
If X is a reflexive Banach space, then every bounded sequence in X has a weakly convergent subsequence.
(the two are actually equivalent, so (*) holds true, but that's not clear from the article). —Preceding unsigned comment added by 84.191.204.239 (talk) 15:45, 17 March 2009 (UTC)