User:Greg L/Delimitnum sandbox#3960-count progression
All: Please feel free to edit and supplement this page as you see fit to facilitate your efforts with the
=Delimitnum sandbox=
This section can be used as a proof-checking sandbox for a
:Hand Coded:
:In the following section, wherever numeric equalities are shown in ‘concise form’ — such as 1.85487(14) × 1043 Hz, —the two digits between the parentheses denotes the uncertainty at 1σ standard deviation (68% confidence level) in the two least significant digits of the significand.
:Template using
:In the following section, wherever numeric equalities are shown in ‘concise form’ — such as {{User:Zocky/delimitnum|1.85487|14|43|Hz}}, —the two digits between the parentheses denotes the uncertainty at 1σ standard deviation (68% confidence level) in the two least significant digits of the significand.
Many times, paragraphs will be indented at their start if the preceding paragraph contains an unclosed span tag. Unclosed spans and weird stuff left over from templates might even make separate paragraphs glue together and other odd behavior. So if I use a bunch of template-generated numbers like this: {{User:Zocky/delimitnum|6.02214179|30|23}} and these: {{User:Zocky/delimitnum|1579800.298728}} and {{User:Zocky/delimitnum|1.356392733||50|Hz}} and {{User:Zocky/delimitnum|0.45359237|||kg}} and {{User:Zocky/delimitnum|6.022461}} and {{User:Zocky/delimitnum|6.0224613}} and {{User:Zocky/delimitnum|1.85487|14|43|Hz}} and finally, this one: {{User:Zocky/delimitnum|6.022461342}}, does the following paragraph line up?
Maybe this paragraph (which also begins with an nice, upright M) lines up with the above one. This paragraph was not set off from the previous one using either
Maybe a short paragraph containing this: {{User:Zocky/delimitnum|6.02214179|30|23}}
Maybe a short paragraph containing this: {{User:Zocky/delimitnum|1579800.29}}
Maybe a short paragraph containing this: {{User:Zocky/delimitnum|1.356392733||50|Hz}}
Maybe a short paragraph containing this: {{User:Zocky/delimitnum|0.45359237|||kg}}
Maybe a short paragraph containing this: {{User:Zocky/delimitnum|1.85487|14|43|Hz}}
Maybe a short paragraph containing no value. Do they all left-justify?
As of this writing, everything lines up perfectly. Greg L (my talk) 23:34, 7 March 2008 (UTC)
Copied below, is some additional example text verbatim from Kilogram. This is to double check whether an unclosed span tag
Template using
Similarly, the avoirdupois pound, used in both the Imperial system and U.S. customary units, is a unit of mass and its related unit of force is the pound-force. The avoirdupois pound is defined as exactly {{User:Zocky/delimitnum|0.45359237|||kg}}, making one kilogram approximately equal to 2.205 avoirdupois pounds.
This new definition of the kilogram proposes to fix the Avogadro constant at precisely {{User:Zocky/delimitnum|6.02214179||23|}} and the kilogram would be defined as “the mass equal to that of 83⅓ × {{User:Zocky/delimitnum|6.02214179||23|}} atoms of carbon-12.”
Techniques to enrich the silicon until it is nearly pure silicon-28, which has an atomic mass of {{User:Zocky/delimitnum|27.9769271|7||g/mole}}. With this approach, the Avogadro constant would not only be fixed, but so too would the atomic mass of silicon-28. As such, the definition of the kilogram would be decoupled from carbon-12 and the kilogram would instead be defined as 1000/{{User:Zocky/delimitnum|27.976927|||}} × {{User:Zocky/delimitnum|6.02214179||23|}} atoms of silicon-28 (≅{{User:Zocky/delimitnum|35.7437397|||}} fixed moles of silicon-28 atoms).
A variation on a carbon-12-based definition proposes to define the Avogadro constant as being precisely 84,446,8863
(≅{{User:Zocky/delimitnum|6.02214098||23|}}) atoms.
Ultimately, the watt balance would define the kilogram in terms of the Planck constant, which is a measure that relates the energy of photons to their frequency. The Planck constant would be fixed, where h = {{User:Zocky/delimitnum|6.62606896||–34|J·s}} (from the 2006 CODATA value of {{User:Zocky/delimitnum|6.62606896|33|–34|J·s}}) and the kilogram would be defined as “the mass of a body at rest whose equivalent energy equals the energy of photons whose frequencies sum to {{User:Zocky/delimitnum|1.356392733||50|Hz}}.”
Hand Coded:
Similarly, the avoirdupois pound, used in both the Imperial system and U.S. customary units, is a unit of mass and its related unit of force is the pound-force. The avoirdupois pound is defined as exactly 0.45359237 kg, making one kilogram approximately equal to 2.205 avoirdupois pounds.
This new definition of the kilogram proposes to fix the Avogadro constant at precisely 6.02214179 × 1023 and the kilogram would be defined as “the mass equal to that of 83⅓ × 6.02214179 × 1023 atoms of carbon-12.”
Techniques to enrich the silicon until it is nearly pure silicon-28, which has an atomic mass of 27.9769271(7) g/mol. With this approach, the Avogadro constant would not only be fixed, but so too would the atomic mass of silicon-28. As such, the definition of the kilogram would be decoupled from carbon-12 and the kilogram would instead be defined as 1000/27.9769271 × 6.02214179 × 1023 atoms of silicon-28 (≅35.7437397 fixed moles of silicon-28 atoms).
A variation on a carbon-12-based definition proposes to define the Avogadro constant as being precisely 84,446,8863 (≅6.02214098 × 1023) atoms. Ultimately, the watt balance would define the kilogram in terms of the Planck constant, which is a measure that relates the energy of photons to their frequency. The Planck constant would be fixed, where h = 6.62606896 × 10–34 J·s (from the 2006 CODATA value of 6.62606896(33) × 10–34 J·s) and the kilogram would be defined as “the mass of a body at rest whose equivalent energy equals the energy of photons whose frequencies sum to 1.356392733 × 1050 Hz.”
===Progressions of features and digits:===
Experiment with narrow spans alongside × sign
With
6.022141791(30)×1023 kg
6.022141791×1023 kg
6.022141792×1023 kg
6.022141793×1023 kg
6.022141794×1023 kg
6.022141795×1023 kg
6.022141796×1023 kg
6.022141797×1023 kg
6.022141798×1023 kg
6.022141799×1023 kg
Conventional way:
===3960-count progression===
====TWO-DIGIT GROUPS FOLLOWING ALL TEN POSSIBLE DIGITS (10 × 100)====
====THREE-DIGIT GROUPS (1 × 1000)=====
====FOUR-DIGIT GROUPS (1 × 1000)====
===Known bugs===
- I created an Excel spreadsheet to help me identify breaks in the progression. Here is a more concise list:
0.1250130.1250210.1250410.1250480.1250690.1250750.1250970.125101–0.1251040.1251240.1251310.1251530.1251860.1252080.1252140.1252360.1252410.125263–0.1252710.1252910.1252980.1253190.1253250.1253460.1253530.125375–0.1253810.125402–0.1254080.125431–0.1254360.1254570.1254850.1254920.1255130.1255200.125541–0.1255470.1255680.1255750.125596–0.1256030.125624–0.125631
* For convenience, I’ve here provided a triple-view of some of the above. They parse as follows:input→ live template return / (at time of this posting)0.125402→ {{User:Zocky/delimitnum|0.125402}} / (0.125 402) ✓ The following are all supposed to end with three-digit groups0.125403→ {{User:Zocky/delimitnum|0.125403}} / (0.125 402)0.125404→ {{User:Zocky/delimitnum|0.125404}} / (0.125 403)0.125405→ {{User:Zocky/delimitnum|0.125405}} / (0.125 404)0.125406→ {{User:Zocky/delimitnum|0.125406}} / (0.125 405)0.125407→ {{User:Zocky/delimitnum|0.125407}} / (0.125 407) ✓0.125408→ {{User:Zocky/delimitnum|0.125408}} / (0.125 407)0.125431→ {{User:Zocky/delimitnum|0.125431}} / (0.125 43)0.125432→ {{User:Zocky/delimitnum|0.125432}} / (0.125 431)0.125433→ {{User:Zocky/delimitnum|0.125433}} / (0.125 433) ✓0.125434→ {{User:Zocky/delimitnum|0.125434}} / (0.125 433)0.125435→ {{User:Zocky/delimitnum|0.125435}} / (0.125 434)0.125436→ {{User:Zocky/delimitnum|0.125436}} / (0.125 436) ✓0.1235436→ {{User:Zocky/delimitnum|0.1235436}} / (0.123 543 599) This one is supposed to end with the four-digit group “5436”0.29872821