Wikipedia:Reference desk/Archives/Mathematics/2012 September 11#R.5BX.5D.2F.28X.5E2-1.29
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A countanle <math> \pi - weight</math>
Hi,
Does anyone know what is a (countable) A countanle for a topological space?
And also, is there a difference between to . In other notation: is there a difference between
to ?.
Thanks!
Topologia clalit (talk) 11:14, 11 September 2012 (UTC)
:Don't know about pi-weights. For the second question, let A in R be a closed interval union a point. Staecker (talk) 11:35, 11 September 2012 (UTC)
:The π-weight of a space is a minimal cardinality of its π-base.—Emil J. 12:05, 11 September 2012 (UTC)
Thank you both!
Topologia clalit (talk) 13:12, 12 September 2012 (UTC)
R[X]/(X^2-1)
If I have a Field (eg R) and I build the quotient as follows R[X]/(p(x))
with a polynomial p(x), then I get a field extension as usual if p(x) is a minimal polynomial.
What happens if p(x) is reducible (ie. not a minimal polynomial)? For example in the cases:
R[X]/(X^2-1)
or
R[X]/(X^2)
--helohe (talk) 19:45, 11 September 2012 (UTC)
:The result will not be a field, but a ring with zero divisors. —Kusma (t·c) 20:13, 11 September 2012 (UTC)
:: in the case R[X]/(X^2) I guessed it will be something like a subset of R x Z/4Z . Does that make sense? --helohe (talk) 20:24, 11 September 2012 (UTC)
:::R[X]/(X2-1) is isomorphic to the group ring R[Z/2Z], but I don't know if you can phrase R[X]/(X2) in a similar way. Rckrone (talk) 00:08, 12 September 2012 (UTC)
:::: R[X]/(X2-1) is also isomorphic to the ring of the Split-complex numbers, and R[X]/(X2) is isomorphic to the ring of dual numbers --84.229.150.202 (talk) 04:40, 12 September 2012 (UTC)
:If the polynomial p is square-free, you can write it as a product of irreducible polynomials. Then the Chinese remainder theorem ensures that the ring is isomorphic to the product of fields . In particular, if R is a field of characteristic other than 2, then is just .—Emil J. 09:15, 12 September 2012 (UTC)