1826 Pennsylvania gubernatorial election

{{Infobox election

| election_name = 1826 Pennsylvania gubernatorial election

| country = Pennsylvania

| type = presidential

| election_date = {{Start date|1826|10|10}}

| ongoing = no

| previous_election = 1823 Pennsylvania gubernatorial election

| previous_year = 1823

| next_election = 1829 Pennsylvania gubernatorial election

| next_year = 1829

| image_size = 125px

| image1 = Shulze.jpg

| party1 = Jacksonian Party (United States)

| nominee1 = John Andrew Shulze

| popular_vote1 = 72,710

| percentage1 = 96.9%

| map_image = 1826 Pennsylvania gubernatorial election results map by county.svg

| map_size = 200px

| map_caption = County Results
Shulze: {{legend0|#6674de|60-70%}} {{legend0|#584cde|70-80%}} {{legend0|#3933e5|80-90%}} {{legend0|#0d0596|90-100%}}
Sergeant: {{legend0|#d38d5f|50-60%}}

| title = Governor

| before_election = John Andrew Shulze

| before_party = Democratic Party (United States)

| after_election = John Andrew Shulze

| after_party = Democratic Party (United States)

}}

The 1826 Pennsylvania gubernatorial election occurred on October 10, 1826. Incumbent governor, John Andrew Shulze, defeated Federalist candidate John Sergeant by a wide margin.

Results

{{Election box begin no change |title = Pennsylvania gubernatorial election, 1826{{cite book |last1=Dubin |first1=Michael J. |title=United States Gubernatorial Elections, 1776-1860: The Official Results by State and County |date=2003 |publisher=McFarland |location=Jefferson, N. C. |page=220 |url=https://archive.org/details/unitedstatesgube0000dubi/page/220/mode/2up}}}}

{{Election box winning candidate with party link no change

|party = Jacksonian Party (United States)

|candidate = John Andrew Shulze (incumbent)

|votes = 72,710

|percentage = 96.87

}}

{{Election box candidate with party link no change

|party = Anti-Jacksonian Party (United States)

|candidate = John Sergeant

|votes = 1,175

|percentage = 1.57

}}