Kruskal's tree theorem#Friedman's finite form
{{short description|Well-quasi-ordering of finite trees}}
{{Redirect|TREE||Tree|and|Tree (disambiguation)}}
In mathematics, Kruskal's tree theorem states that the set of finite trees over a well-quasi-ordered set of labels is itself well-quasi-ordered under homeomorphic embedding.
A finitary application of the theorem gives the existence of the fast-growing TREE function. TREE(3) is largely accepted to be one of the largest simply defined finite numbers, dwarfing other large numbers such as Graham's number and googolplex.{{Cite web |date=2017-10-20 |title=The Enormity of the Number TREE(3) Is Beyond Comprehension |url=https://www.popularmechanics.com/science/math/a28725/number-tree3/ |access-date=2025-02-04 |website=Popular Mechanics |language=en-US}}
History
The theorem was conjectured by Andrew Vázsonyi and proved by {{harvs|txt=yes|year= 1960 |authorlink=Joseph Kruskal|last=Kruskal|first=Joseph}}; a short proof was given by {{harvs|txt=yes|year= 1963|authorlink=Crispin St. J. A. Nash-Williams|last=Nash-Williams|first=Crispin}}. It has since become a prominent example in reverse mathematics as a statement that cannot be proved in ATR0 (a second-order arithmetic theory with a form of arithmetical transfinite recursion).
In 2004, the result was generalized from trees to graphs as the Robertson–Seymour theorem, a result that has also proved important in reverse mathematics and leads to the even-faster-growing SSCG function, which dwarfs .
Statement
The version given here is that proven by Nash-Williams; Kruskal's formulation is somewhat stronger. All trees we consider are finite.
Given a tree {{mvar|T}} with a root, and given vertices {{mvar|v}}, {{mvar|w}}, call {{mvar|w}} a successor of {{mvar|v}} if the unique path from the root to {{mvar|w}} contains {{mvar|v}}, and call {{mvar|w}} an immediate successor of {{mvar|v}} if additionally the path from {{mvar|v}} to {{mvar|w}} contains no other vertex.
Take {{mvar|X}} to be a partially ordered set. If {{math|T1}}, {{math|T2}} are rooted trees with vertices labeled in {{mvar|X}}, we say that {{math|T1}} is inf-embeddable in {{math|T2}} and write if there is an injective map {{mvar|F}} from the vertices of {{math|T1}} to the vertices of {{math|T2}} such that:
- For all vertices {{mvar|v}} of {{math|T1}}, the label of {{mvar|v}} precedes the label of ;
- If {{mvar|w}} is any successor of {{mvar|v}} in {{math|T1}}, then is a successor of ; and
- If {{math|w1}}, {{math|w2}} are any two distinct immediate successors of {{mvar|v}}, then the path from to in {{math|T2}} contains .
Kruskal's tree theorem then states:
If {{mvar|X}} is well-quasi-ordered, then the set of rooted trees with labels in {{mvar|X}} is well-quasi-ordered under the inf-embeddable order defined above. (That is to say, given any infinite sequence {{math|T1, T2, …}} of rooted trees labeled in {{mvar|X}}, there is some
Friedman's work
For a countable label set {{mvar|X}}, Kruskal's tree theorem can be expressed and proven using second-order arithmetic. However, like Goodstein's theorem or the Paris–Harrington theorem, some special cases and variants of the theorem can be expressed in subsystems of second-order arithmetic much weaker than the subsystems where they can be proved. This was first observed by Harvey Friedman in the early 1980s, an early success of the {{nowrap|then-nascent}} field of reverse mathematics. In the case where the trees above are taken to be unlabeled (that is, in the case where {{mvar|X}} has size one), Friedman found that the result was unprovable in ATR0,{{harvnb|Simpson|1985|at=Theorem 1.8}} thus giving the first example of a predicative result with a provably impredicative proof.{{harvnb|Friedman|2002|p=60}} This case of the theorem is still provable by Π{{su|p=1|b=1}}-CA0, but by adding a "gap condition"{{harvnb|Simpson|1985|at=Definition 4.1}} to the definition of the order on trees above, he found a natural variation of the theorem unprovable in this system.{{harvnb|Simpson|1985|at=Theorem 5.14}}{{harvnb|Marcone|2005|pp=8–9}} Much later, the Robertson–Seymour theorem would give another theorem unprovable by Π{{su|p=1|b=1}}-CA0.
Ordinal analysis confirms the strength of Kruskal's theorem, with the proof-theoretic ordinal of the theorem equaling the small Veblen ordinal (sometimes confused with the smaller Ackermann ordinal).{{sfn|Rathjen|Weiermann|1993}}
Weak tree function
Suppose that
:There is some {{mvar|m}} such that if {{math|T1, ..., Tm}} is a finite sequence of unlabeled rooted trees where {{Mvar|Ti}} has
All the statements
TREE function
By incorporating labels, Friedman defined a far faster-growing function.{{Cite web |last=Friedman |first=Harvey |date=28 March 2006 |title=273:Sigma01/optimal/size |url=http://www.cs.nyu.edu/pipermail/fom/2006-March/010279.html |access-date=8 August 2017 |website=Ohio State University Department of Maths}} For a positive integer {{Var|{{math|n}}}}, take
: There is a sequence {{math|T1, ..., Tm}} of rooted trees labelled from a set of {{mvar|n}} labels, where each {{Mvar|Ti}} has at most {{Mvar|i}} vertices, such that
The TREE sequence begins
See also
Notes
:{{note label|TR|a|^ a}} Friedman originally denoted this function by TR[n].
:{{note label|n_k|b|^ b}} n(k) is defined as the length of the longest possible sequence that can be constructed with a k-letter alphabet such that no block of letters xi,...,x2i is a subsequence of any later block xj,...,x2j.{{Cite web |last=Friedman |first=Harvey M. |date=8 October 1998 |title=Long Finite Sequences |url=https://u.osu.edu/friedman.8/files/2014/01/LongFinSeq98-2f0wmq3.pdf |access-date=8 August 2017 |website=Ohio State University Department of Mathematics |pages=5, 48 (Thm.6.8)}}
:{{note label|Ackermann|c|^ c}} A(x) taking one argument, is defined as A(x, x), where A(k, n), taking two arguments, is a particular version of Ackermann's function defined as: A(1, n) = 2n, A(k+1, 1) = A(k, 1), A(k+1, n+1) = A(k, A(k+1, n)).
References
Citations
{{reflist}}
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{{Large numbers}}
{{Order theory}}
{{Use dmy dates|date=March 2024}}