Sigma-additive set function#modularity

{{Short description|Mapping function}}

{{mcn|date=April 2024}}

In mathematics, an additive set function is a function \mu mapping sets to numbers, with the property that its value on a union of two disjoint sets equals the sum of its values on these sets, namely, \mu(A \cup B) = \mu(A) + \mu(B). If this additivity property holds for any two sets, then it also holds for any finite number of sets, namely, the function value on the union of k disjoint sets (where k is a finite number) equals the sum of its values on the sets. Therefore, an additive set function is also called a finitely additive set function (the terms are equivalent). However, a finitely additive set function might not have the additivity property for a union of an infinite number of sets. A σ-additive set function is a function that has the additivity property even for countably infinite many sets, that is, \mu\left(\bigcup_{n=1}^\infty A_n\right) = \sum_{n=1}^\infty \mu(A_n).

Additivity and sigma-additivity are particularly important properties of measures. They are abstractions of how intuitive properties of size (length, area, volume) of a set sum when considering multiple objects. Additivity is a weaker condition than σ-additivity; that is, σ-additivity implies additivity.

The term modular set function is equivalent to additive set function; see modularity below.

Additive (or finitely additive) set functions

Let \mu be a set function defined on an algebra of sets \scriptstyle\mathcal{A} with values in [-\infty, \infty] (see the extended real number line). The function \mu is called {{visible anchor|additive|additive set function}} or {{visible anchor|finitely additive|finitely additive set function}}, if whenever A and B are disjoint sets in \scriptstyle\mathcal{A}, then

\mu(A \cup B) = \mu(A) + \mu(B).

A consequence of this is that an additive function cannot take both - \infty and + \infty as values, for the expression \infty - \infty is undefined.

One can prove by mathematical induction that an additive function satisfies

\mu\left(\bigcup_{n=1}^N A_n\right)=\sum_{n=1}^N \mu\left(A_n\right)

for any A_1, A_2, \ldots, A_N disjoint sets in \mathcal{A}.

σ-additive set functions

Suppose that \scriptstyle\mathcal{A} is a σ-algebra. If for every sequence A_1, A_2, \ldots, A_n, \ldots of pairwise disjoint sets in \scriptstyle\mathcal{A},

\mu\left(\bigcup_{n=1}^\infty A_n\right) = \sum_{n=1}^\infty \mu(A_n),

holds then \mu is said to be {{em|countably additive}} or {{em|{{sigma}}-additive}}.

Every {{sigma}}-additive function is additive but not vice versa, as shown below.

τ-additive set functions

Suppose that in addition to a sigma algebra \mathcal{A}, we have a topology \tau. If for every directed family of measurable open sets \mathcal{G} \subseteq \mathcal{A} \cap \tau,

\mu\left(\bigcup \mathcal{G} \right) = \sup_{G\in\mathcal{G}} \mu(G),

we say that \mu is \tau-additive. In particular, if \mu is inner regular (with respect to compact sets) then it is \tau-additive.D. H. Fremlin Measure Theory, Volume 4, Torres Fremlin, 2003.

Properties

Useful properties of an additive set function \mu include the following.

=Value of empty set=

Either \mu(\varnothing) = 0, or \mu assigns \infty to all sets in its domain, or \mu assigns - \infty to all sets in its domain. Proof: additivity implies that for every set A, \mu(A) = \mu(A \cup \varnothing) = \mu(A) + \mu( \varnothing) (it's possible in the edge case of an empty domain that the only choice for A is the empty set itself, but that still works). If \mu(\varnothing) \neq 0, then this equality can be satisfied only by plus or minus infinity.

=Monotonicity=

If \mu is non-negative and A \subseteq B then \mu(A) \leq \mu(B). That is, \mu is a {{visible anchor|monotone set function}}. Similarly, If \mu is non-positive and A \subseteq B then \mu(A) \geq \mu(B).

=Modularity{{Anchor|modularity}}=

{{See also|Valuation (geometry)}}

{{See also|Valuation (measure theory)}}

A set function \mu on a family of sets \mathcal{S} is called a {{visible anchor|modular set function}} and a Valuation (geometry) if whenever A, B, A\cup B, and A\cap B are elements of \mathcal{S}, then

\phi(A\cup B)+ \phi(A\cap B) = \phi(A) + \phi(B)

The above property is called {{visible anchor|modularity}} and the argument below proves that additivity implies modularity.

Given A and B, \mu(A \cup B) + \mu(A \cap B) = \mu(A) + \mu(B). Proof: write A = (A \cap B) \cup (A \setminus B) and B = (A \cap B) \cup (B \setminus A) and A \cup B = (A \cap B) \cup (A \setminus B) \cup (B \setminus A), where all sets in the union are disjoint. Additivity implies that both sides of the equality equal \mu(A \setminus B) + \mu(B \setminus A) + 2\mu(A \cap B).

However, the related properties of submodularity and subadditivity are not equivalent to each other.

Note that modularity has a different and unrelated meaning in the context of complex functions; see modular form.

=Set difference=

If A \subseteq B and \mu(B) - \mu(A) is defined, then \mu(B \setminus A) = \mu(B) - \mu(A).

Examples

An example of a {{sigma}}-additive function is the function \mu defined over the power set of the real numbers, such that

\mu (A)= \begin{cases} 1 & \mbox{ if } 0 \in A \\

0 & \mbox{ if } 0 \notin A.

\end{cases}

If A_1, A_2, \ldots, A_n, \ldots is a sequence of disjoint sets of real numbers, then either none of the sets contains 0, or precisely one of them does. In either case, the equality

\mu\left(\bigcup_{n=1}^\infty A_n\right) = \sum_{n=1}^\infty \mu(A_n)

holds.

See measure and signed measure for more examples of {{sigma}}-additive functions.

A charge is defined to be a finitely additive set function that maps \varnothing to 0.{{Cite book|last=Bhaskara Rao|first=K. P. S.|first2=M. |last2=Bhaskara Rao|url=https://www.worldcat.org/oclc/21196971|title=Theory of charges: a study of finitely additive measures|date=1983|publisher=Academic Press|isbn=0-12-095780-9|location=London|pages=35|oclc=21196971}} (Cf. ba space for information about bounded charges, where we say a charge is bounded to mean its range is a bounded subset of R.)

=An additive function which is not σ-additive=

An example of an additive function which is not σ-additive is obtained by considering \mu, defined over the Lebesgue sets of the real numbers \R by the formula

\mu(A) = \lim_{k\to\infty} \frac{1}{k} \cdot \lambda(A \cap (0,k)),

where \lambda denotes the Lebesgue measure and \lim the Banach limit. It satisfies 0 \leq \mu(A) \leq 1 and if \sup A < \infty then \mu(A) = 0.

One can check that this function is additive by using the linearity of the limit. That this function is not σ-additive follows by considering the sequence of disjoint sets

A_n = [n,n + 1)

for n = 0, 1, 2, \ldots The union of these sets is the positive reals, and \mu applied to the union is then one, while \mu applied to any of the individual sets is zero, so the sum of \mu(A_n) is also zero, which proves the counterexample.

Generalizations

One may define additive functions with values in any additive monoid (for example any group or more commonly a vector space). For sigma-additivity, one needs in addition that the concept of limit of a sequence be defined on that set. For example, spectral measures are sigma-additive functions with values in a Banach algebra. Another example, also from quantum mechanics, is the positive operator-valued measure.

See also

  • {{annotated link|Additive map}}
  • {{annotated link|Hahn–Kolmogorov theorem}}
  • {{annotated link|Measure (mathematics)}}
  • {{annotated link|σ-finite measure}}
  • {{annotated link|Signed measure}}
  • {{annotated link|Submodular set function}}
  • {{annotated link|Subadditive set function}}
  • {{annotated link|τ-additivity}}
  • ba space – The set of bounded charges on a given sigma-algebra

{{PlanetMath attribution|id=3400|title=additive}}

References

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Category:Measure theory

Category:Additive functions