frustum

{{Short description|Portion of a solid that lies between two parallel planes cutting the solid}}

{{other uses}}

{{multiple image

| image1 = Pentagonal frustum.svg

| image2 = Usech kvadrat piramid.png

| total_width = 450

| footer = Pentagonal frustum and square frustum

}}

In geometry, a {{langnf|la|frustum|italic=no|morsel}};{{efn|The term frustum comes {{etymology|la|{{wikt-lang|la|frustum}}|}}, meaning 'piece' or 'morsel". The English word is often misspelled as {{sic|hide=y|frus|trum}}, a different Latin word cognate to the English word "frustrate".{{cite book |title=Teachers' Manual: Books I–VIII. For Prang's complete course in form-study and drawing, Books 7–8 |first=John Spencer|last=Clark |publisher=Prang Educational Company |year=1895 |page=49 |url=https://books.google.com/books?id=83EBAAAAYAAJ&pg=PA49}} The confusion between these two words is very old: a warning about them can be found in the Appendix Probi, and the works of Plautus include a pun on them.{{cite book |title=Funny Words in Plautine Comedy |first=Michael|last=Fontaine |publisher=Oxford University Press |year=2010 |isbn=9780195341447 |url=https://books.google.com/books?id=SFPUvjlSUIsC&pg=PA117 |pages=117, 154}}}} ({{plural form}}: frusta or frustums) is the portion of a solid (normally a pyramid or a cone) that lies between two parallel planes cutting the solid. In the case of a pyramid, the base faces are polygonal and the side faces are trapezoidal. A right frustum is a right pyramid or a right cone truncated perpendicularly to its axis;{{cite book |first1=William F.|last1=Kern |first2=James R.|last2=Bland |title=Solid Mensuration with Proofs |year=1938 |page=67}} otherwise, it is an oblique frustum.

In a truncated cone or truncated pyramid, the truncation plane is {{em|not}} necessarily parallel to the cone's base, as in a frustum.

If all its edges are forced to become of the same length, then a frustum becomes a prism (possibly oblique or/and with irregular bases).

Formulas

=Volume=

The formula for the volume of a pyramidal square frustum was introduced by the ancient Egyptian mathematics in what is called the Moscow Mathematical Papyrus, written in the 13th dynasty ({{circa|1850 BC}}):

:V = \frac{h}{3}\left(a^2 + ab + b^2\right),

where {{mvar|a}} and {{mvar|b}} are the base and top side lengths, and {{mvar|h}} is the height.

The Egyptians knew the correct formula for the volume of such a truncated square pyramid, but no proof of this equation is given in the Moscow papyrus.

The volume of a conical or pyramidal frustum is the volume of the solid before slicing its "apex" off, minus the volume of this "apex":

:V = \frac{h_1 B_1 - h_2 B_2}{3},

where {{math|B1}} and {{math|B2}} are the base and top areas, and {{math|h1}} and {{math|h2}} are the perpendicular heights from the apex to the base and top planes.

Considering that

:\frac{B_1}{h_1^2} = \frac{B_2}{h_2^2} = \frac{\sqrt{B_1B_2}}{h_1h_2} = \alpha,

the formula for the volume can be expressed as the third of the product of this proportionality, \alpha, and of the difference of the cubes of the heights {{math|h1}} and {{math|h2}} only:

:V = \frac{h_1 \alpha h_1^2 - h_2 \alpha h_2^2}{3} = \alpha\frac{h_1^3 - h_2^3}{3}.

By using the identity {{math|1=a3b3 = (ab)(a2 + ab + b2)}}, one gets:

:V = (h_1 - h_2)\alpha\frac{h_1^2 + h_1h_2 + h_2^2}{3},

where {{math|1=h1h2 = h}} is the height of the frustum.

Distributing \alpha and substituting from its definition, the Heronian mean of areas {{math|B1}} and {{math|B2}} is obtained:

:\frac{B_1 + \sqrt{B_1B_2} + B_2}{3};

the alternative formula is therefore:

:V = \frac{h}{3}\left(B_1 + \sqrt{B_1B_2} + B_2\right).

Heron of Alexandria is noted for deriving this formula, and with it, encountering the imaginary unit: the square root of negative one.Nahin, Paul. An Imaginary Tale: The story of {{sqrt|−1}}. Princeton University Press. 1998

In particular:

  • The volume of a circular cone frustum is:

::V = \frac{\pi h}{3}\left(r_1^2 + r_1r_2 + r_2^2\right),

:where {{math|r1}} and {{math|r2}} are the base and top radii.

  • The volume of a pyramidal frustum whose bases are regular {{mvar|n}}-gons is:

::V = \frac{nh}{12}\left(a_1^2 + a_1a_2 + a_2^2\right)\cot\frac{\pi}{n},

:where {{math|a1}} and {{math|a2}} are the base and top side lengths.

:Image:Frustum with symbols.svg

=Surface area=

File:CroppedCone.svg

File:Tronco cono 3D.stl

For a right circular conical frustum{{cite web |url=http://www.mathwords.com/f/frustum.htm |title=Mathwords.com: Frustum |access-date=17 July 2011}}{{cite journal|doi=10.1080/10407782.2017.1372670 |first1=Ahmed T. |last1=Al-Sammarraie |first2=Kambiz |last2=Vafai |date=2017 |title=Heat transfer augmentation through convergence angles in a pipe |journal=Numerical Heat Transfer, Part A: Applications |volume=72 |issue=3 |page=197−214|bibcode=2017NHTA...72..197A |s2cid=125509773 }} the slant height s is

{{bi|left=1.6|\displaystyle s=\sqrt{\left(r_1-r_2\right)^2+h^2},}}

the lateral surface area is

{{bi|left=1.6|\displaystyle \pi\left(r_1+r_2\right)s,}}

and the total surface area is

{{bi|left=1.6|\displaystyle \pi\left(\left(r_1+r_2\right)s+r_1^2+r_2^2\right),}}

where r1 and r2 are the base and top radii respectively.

Examples

File:Rolo-Candies-US.jpg brand chocolates approximate a right circular conic frustum, although not flat on top. ]]

See also

Notes

{{Notelist}}

References

{{Reflist}}