weak base

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{{Acids and bases}}

A weak base is a base that, upon dissolution in water, does not dissociate completely, so that the resulting aqueous solution contains only a small proportion of hydroxide ions and the concerned basic radical, and a large proportion of undissociated molecules of the base.

pH, K<sub>b</sub>, and K<sub>w</sub>

Bases yield solutions in which the hydrogen ion activity is lower than it is in pure water, i.e., the solution is said to have a pH greater than 7.0 at standard conditions, potentially as high as 14 (and even greater than 14 for some bases). The formula for pH is:

:\mbox{pH} = -\log_{10} \left[ \mbox{H}^+ \right]

Bases are proton acceptors; a base will receive a hydrogen ion from water, H2O, and the remaining H+ concentration in the solution determines pH. A weak base will have a higher H+ concentration than a stronger base because it is less completely protonated than a stronger base and, therefore, more hydrogen ions remain in its solution. Given its greater H+ concentration, the formula yields a lower pH value for the weak base. However, pH of bases is usually calculated in terms of the OH concentration. This is done because the H+ concentration is not a part of the reaction, whereas the OH concentration is. The pOH is defined as:

:\mbox{pOH} = -\log_{10} \left[ \mbox{OH}^- \right]

If we multiply the equilibrium constants of a conjugate acid (such as NH4+) and a conjugate base (such as NH3) we obtain:

: K_a \times K_b = {[H_3O^+] [NH_3]\over[NH_4^+]} \times {[NH_4^+] [OH^-]\over[NH_3]} = [H_3O^+] [OH^-]

As {K_w} = [H_3O^+] [OH^-] is just the self-ionization constant of water, we have K_a \times K_b = K_w

Taking the logarithm of both sides of the equation yields:

:logK_a + logK_b = logK_w

Finally, multiplying both sides by -1, we obtain:

:pK_a + pK_b = pK_w = 14.00

With pOH obtained from the pOH formula given above, the pH of the base can then be calculated from pH = pK_w - pOH, where pKw = 14.00.

A weak base persists in chemical equilibrium in much the same way as a weak acid does, with a base dissociation constant (Kb) indicating the strength of the base. For example, when ammonia is put in water, the following equilibrium is set up:

:\mathrm{K_b={[NH_4^+] [OH^-]\over[NH_3]}}

A base that has a large Kb will ionize more completely and is thus a stronger base. As shown above, the pH of the solution, which depends on the H+ concentration, increases with increasing OH concentration; a greater OH concentration means a smaller H+ concentration, therefore a greater pH. Strong bases have smaller H+ concentrations because they are more fully protonated, leaving fewer hydrogen ions in the solution. A smaller H+ concentration means a greater OH concentration and, therefore, a greater Kb and a greater pH.

NaOH (s) (sodium hydroxide) is a stronger base than (CH3CH2)2NH (l) (diethylamine) which is a stronger base than NH3 (g) (ammonia). As the bases get weaker, the smaller the Kb values become.{{cite web|url=http://www.chemguide.co.uk/physical/acidbaseeqia/bases.html|title=Explanation of strong and weak bases]|publisher=ChemGuide|access-date=2018-03-23}}

Percentage protonated

As seen above, the strength of a base depends primarily on pH. To help describe the strengths of weak bases, it is helpful to know the percentage protonated-the percentage of base molecules that have been protonated. A lower percentage will correspond with a lower pH because both numbers result from the amount of protonation. A weak base is less protonated, leading to a lower pH and a lower percentage protonated.{{cite book|author=Howard Maskill|title=The physical basis of organic chemistry|url=https://books.google.com/books?id=4AXwAAAAMAAJ|year=1985|publisher=Oxford University Press, Incorporated|isbn=978-0-19-855192-8}}

The typical proton transfer equilibrium appears as such:

:B(aq) + H_2O(l) \leftrightarrow HB^+(aq) + OH^-(aq)

B represents the base.

:Percentage\ protonated = {molarity\ of\ HB^+ \over\ initial\ molarity\ of\ B} \times 100\% = {[{HB}^+]\over [B]_{initial}} {\times 100\%}

In this formula, [B]initial is the initial molar concentration of the base, assuming that no protonation has occurred.

A typical pH problem

Calculate the pH and percentage protonation of a .20 M aqueous solution of pyridine, C5H5N. The Kb for C5H5N is 1.8 x 10−9.{{cite web|url=http://www.kentchemistry.com/links/AcidsBases/pHWeakBases.htm|title=Calculations of weak bases|publisher=Mr Kent's Chemistry Page|access-date=2018-03-23}}

First, write the proton transfer equilibrium:

:\mathrm{H_2O(l) + C_5H_5N(aq) \leftrightarrow C_5H_5NH^+ (aq) + OH^- (aq)}

:K_b=\mathrm{[C_5H_5NH^+] [OH^-]\over [C_5H_5N]}

The equilibrium table, with all concentrations in moles per liter, is

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|+

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! !! C5H5N !! C5H6N+ !! OH

initial normality

| .20 || 0 || 0

change in normality

| -x || +x || +x

equilibrium normality

| .20 -x || x || x

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Substitute the equilibrium molarities into the basicity constant

| K_b=\mathrm {1.8 \times 10^{-9}} = {x \times x \over .20-x}

We can assume that x is so small that it will be meaningless by the time we use significant figures.

| \mathrm {1.8 \times 10^{-9}} \approx {x^2 \over .20}

Solve for x.

| \mathrm x \approx \sqrt{.20 \times (1.8 \times 10^{-9})} = 1.9 \times 10^{-5}

Check the assumption that x << .20

| \mathrm 1.9 \times 10^{-5} \ll .20; so the approximation is valid

Find pOH from pOH = -log [OH] with [OH]=x

| \mathrm pOH \approx -log(1.9 \times 10^{-5}) = 4.7

From pH = pKw - pOH,

| \mathrm pH \approx 14.00 - 4.7 = 9.3

From the equation for percentage protonated with [HB+] = x and [B]initial = .20,

| \mathrm percentage \ protonated = {1.9 \times 10^{-5} \over .20} \times 100\% = .0095\%

This means .0095% of the pyridine is in the protonated form of C5H5NH+.

Examples

Simple Facts

  • An example of a weak base is ammonia. It does not contain hydroxide ions, but it reacts with water to produce ammonium ions and hydroxide ions.Atkins, Peter, and Loretta Jones. Chemical Principles: The Quest for Insight, 3rd Ed., New York: W.H. Freeman, 2005.
  • The position of equilibrium varies from base to base when a weak base reacts with water. The further to the left it is, the weaker the base.Clark, Jim. "Strong and Weak Bases."N.p.,2002. Web.
  • When there is a hydrogen ion gradient between two sides of the biological membrane, the concentration of some weak bases are focused on only one side of the membrane.{{Cite journal |doi = 10.1016/0002-9343(58)90376-0|title = Non-ionic diffusion and the excretion of weak acids and bases|journal = The American Journal of Medicine|volume = 24|issue = 5|pages = 709–729|year = 1958|last1 = Milne|first1 = M.D.|last2 = Scribner|first2 = B.H.|last3 = Crawford|first3 = M.A.}} Weak bases tend to build up in acidic fluids. Acid gastric contains a higher concentration of weak base than plasma. Acid urine, compared to alkaline urine, excretes weak bases at a faster rate.

See also

References

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