Euler product#Notable constants

{{Short description|Infinite products of functions indexed by primes}}

In number theory, an Euler product is an expansion of a Dirichlet series into an infinite product indexed by prime numbers. The original such product was given for the sum of all positive integers raised to a certain power as proven by Leonhard Euler. This series and its continuation to the entire complex plane would later become known as the Riemann zeta function.

Definition

In general, if {{mvar|a}} is a bounded multiplicative function, then the Dirichlet series

:\sum_{n=1}^\infty \frac{a(n)}{n^s}

is equal to

:\prod_{p\in\mathbb{P}} P(p, s) \quad \text{for } \operatorname{Re}(s) >1 .

where the product is taken over prime numbers {{mvar|p}}, and {{math|P(p, s)}} is the sum

:\sum_{k=0}^\infty \frac{a(p^k)}{p^{ks}} = 1 + \frac{a(p)}{p^s} + \frac{a(p^2)}{p^{2s}} + \frac{a(p^3)}{p^{3s}} + \cdots

In fact, if we consider these as formal generating functions, the existence of such a formal Euler product expansion is a necessary and sufficient condition that {{math|a(n)}} be multiplicative: this says exactly that {{math|a(n)}} is the product of the {{math|a(pk)}} whenever {{mvar|n}} factors as the product of the powers {{math|pk}} of distinct primes {{mvar|p}}.

An important special case is that in which {{math|a(n)}} is totally multiplicative, so that {{math|P(p, s)}} is a geometric series. Then

:P(p, s)=\frac{1}{1-\frac{a(p)}{p^s}},

as is the case for the Riemann zeta function, where {{math|a(n) {{=}} 1}}, and more generally for Dirichlet characters.

Convergence

In practice all the important cases are such that the infinite series and infinite product expansions are absolutely convergent in some region

:\operatorname{Re}(s) > C,

that is, in some right half-plane in the complex numbers. This already gives some information, since the infinite product, to converge, must give a non-zero value; hence the function given by the infinite series is not zero in such a half-plane.

In the theory of modular forms it is typical to have Euler products with quadratic polynomials in the denominator here. The general Langlands philosophy includes a comparable explanation of the connection of polynomials of degree {{mvar|m}}, and the representation theory for {{math|GLm}}.

Examples

The following examples will use the notation \mathbb{P} for the set of all primes, that is:

:\mathbb{P}=\{p \in \mathbb{N}\,|\,p\text{ is prime}\}.

The Euler product attached to the Riemann zeta function {{math|ζ(s)}}, also using the sum of the geometric series, is

:\begin{align}

\prod_{p\, \in\, \mathbb{P}} \left(\frac{1}{1-\frac{1}{p^s}}\right) &= \prod_{p\ \in\ \mathbb{P}} \left(\sum_{k=0}^{\infty}\frac{1}{p^{ks}}\right) \\

&= \sum_{n=1}^{\infty} \frac{1}{n^s} = \zeta(s).

\end{align}

while for the Liouville function {{math|λ(n) {{=}} (−1)ω(n)}}, it is

: \prod_{p\, \in\, \mathbb{P}} \left(\frac{1}{1+\frac{1}{p^s}}\right) = \sum_{n=1}^{\infty} \frac{\lambda(n)}{n^{s}} = \frac{\zeta(2s)}{\zeta(s)}.

Using their reciprocals, two Euler products for the Möbius function {{math|μ(n)}} are

: \prod_{p\, \in\, \mathbb{P}} \left(1-\frac{1}{p^s}\right) = \sum_{n=1}^{\infty} \frac{\mu (n)}{n^{s}} = \frac{1}{\zeta(s)}

and

: \prod_{p\, \in\, \mathbb{P}} \left(1+\frac{1}{p^s}\right) = \sum_{n=1}^{\infty} \frac

\mu(n)
{n^{s}} = \frac{\zeta(s)}{\zeta(2s)}.

Taking the ratio of these two gives

: \prod_{p\, \in\, \mathbb{P}} \left(\frac{1+\frac{1}{p^s}}{1-\frac{1}{p^s}}\right) = \prod_{p\, \in\, \mathbb{P}} \left(\frac{p^s+1}{p^s-1}\right) = \frac{\zeta(s)^2}{\zeta(2s)}.

Since for even values of {{mvar|s}} the Riemann zeta function {{math|ζ(s)}} has an analytic expression in terms of a rational multiple of {{math|πs}}, then for even exponents, this infinite product evaluates to a rational number. For example, since {{math|ζ(2) {{=}} {{sfrac|π2|6}}}}, {{math|ζ(4) {{=}} {{sfrac|π4|90}}}}, and {{math|ζ(8) {{=}} {{sfrac|π8|9450}}}}, then

:\begin{align}

\prod_{p\, \in\, \mathbb{P}} \left(\frac{p^2+1}{p^2-1}\right) &= \frac53 \cdot \frac{10}{8} \cdot \frac{26}{24} \cdot \frac{50}{48} \cdot \frac{122}{120} \cdots &= \frac{\zeta(2)^2}{\zeta(4)} &= \frac52, \\[6pt]

\prod_{p\, \in\, \mathbb{P}} \left(\frac{p^4+1}{p^4-1}\right) &= \frac{17}{15} \cdot \frac{82}{80} \cdot \frac{626}{624} \cdot \frac{2402}{2400} \cdots &= \frac{\zeta(4)^2}{\zeta(8)} &= \frac76,

\end{align}

and so on, with the first result known by Ramanujan. This family of infinite products is also equivalent to

: \prod_{p\, \in\, \mathbb{P}} \left(1+\frac{2}{p^s}+\frac{2}{p^{2s}}+\cdots\right) = \sum_{n=1}^\infty \frac{2^{\omega(n)}}{n^s} = \frac{\zeta(s)^2}{\zeta(2s)},

where {{math|ω(n)}} counts the number of distinct prime factors of {{mvar|n}}, and {{math|2ω(n)}} is the number of square-free divisors.

If {{math|χ(n)}} is a Dirichlet character of conductor {{mvar|N}}, so that {{mvar|χ}} is totally multiplicative and {{math|χ(n)}} only depends on {{math|n mod N}}, and {{math|χ(n) {{=}} 0}} if {{mvar|n}} is not coprime to {{mvar|N}}, then

: \prod_{p\, \in\, \mathbb{P}} \frac{1}{1- \frac{\chi(p)}{p^s}} = \sum_{n=1}^\infty \frac{\chi(n)}{n^s}.

Here it is convenient to omit the primes {{mvar|p}} dividing the conductor {{mvar|N}} from the product. In his notebooks, Ramanujan generalized the Euler product for the zeta function as

: \prod_{p\, \in\, \mathbb{P}} \left(x-\frac{1}{p^s}\right)\approx \frac{1}{\operatorname{Li}_s (x)}

for {{math|s > 1}} where {{math|Lis(x)}} is the polylogarithm. For {{math|x {{=}} 1}} the product above is just {{math|{{sfrac|1|ζ(s)}}}}.

Notable constants

Many well known constants have Euler product expansions.

The Leibniz formula for {{pi}}

:\frac{\pi}{4} = \sum_{n=0}^\infty \frac{(-1)^n}{2n+1} = 1 - \frac13 + \frac15 - \frac17 + \cdots

can be interpreted as a Dirichlet series using the (unique) Dirichlet character modulo 4, and converted to an Euler product of superparticular ratios (fractions where numerator and denominator differ by 1):

:\frac{\pi}{4} = \left(\prod_{p\equiv 1\pmod 4}\frac{p}{p-1}\right)\left( \prod_{p\equiv 3\pmod 4}\frac{p}{p+1}\right)=\frac34 \cdot \frac54 \cdot \frac78 \cdot \frac{11}{12} \cdot \frac{13}{12} \cdots,

where each numerator is a prime number and each denominator is the nearest multiple of 4.{{citation|title=The Legacy of Leonhard Euler: A Tricentennial Tribute|first=Lokenath|last=Debnath|publisher=World Scientific|year=2010|isbn=9781848165267|page=214|url=https://books.google.com/books?id=K2liU-SHl6EC&pg=PA214}}.

Other Euler products for known constants include:

:: \prod_{p>2} \left(1 - \frac{1}{\left(p-1\right)^2}\right) = 0.660161...

::\begin{align}

\frac{\pi}{4} \prod_{p \equiv 1\pmod 4} \left(1 - \frac{1}{p^2}\right)^\frac12 &= 0.764223... \\[6pt]

\frac{1}{\sqrt{2}} \prod_{p \equiv 3\pmod 4} \left(1 - \frac{1}{p^2}\right)^{-\frac12} &= 0.764223...

\end{align}

:: \prod_{p} \left(1 + \frac{1}{\left(p-1\right)^2}\right) = 2.826419...

:: \prod_{p} \left(1 - \frac{1}{\left(p+1\right)^2}\right) = 0.775883...

:: \prod_{p} \left(1 - \frac{1}{p(p-1)}\right) = 0.373955...

:: \prod_{p} \left(1 + \frac{1}{p(p-1)}\right) = \frac{315}{2\pi^4}\zeta(3) = 1.943596...

:: \prod_{p} \left(1 - \frac{1}{p(p+1)}\right) = 0.704442...

:and its reciprocal {{OEIS2C|A065489}}:

:: \prod_{p} \left(1 + \frac{1}{p^2+p-1}\right) = 1.419562...

:: \frac{1}{2}+\frac{1}{2} \prod_{p} \left(1 - \frac{2}{p^2}\right) = 0.661317...

:: \prod_{p} \left(1 - \frac{1}{p^2(p+1)}\right) = 0.881513...

:: \prod_{p} \left(1 + \frac{1}{p^2(p-1)}\right) = 1.339784...

:: \prod_{p>2} \left(1 - \frac{p+2}{p^3}\right) = 0.723648...

:: \prod_{p} \left(1 - \frac{2p-1}{p^3}\right) = 0.428249...

:: \prod_{p} \left(1 - \frac{3p-2}{p^3}\right) = 0.286747...

:: \prod_{p} \left(1 - \frac{p}{p^3-1}\right) = 0.575959...

:: \prod_{p} \left(1 + \frac{3p^2-1}{p(p+1)\left(p^2-1\right)}\right) = 2.596536...

:: \prod_{p} \left(1 - \frac{3}{p^3}+\frac{2}{p^4}+\frac{1}{p^5}-\frac{1}{p^6}\right) = 0.678234...

:: \prod_{p} \left(1 - \frac{1}{p}\right)^7 \left(1 + \frac{7p+1}{p^2}\right) = 0.0013176...

Notes

{{Reflist}}

References

{{ref begin}}

  • G. Polya, Induction and Analogy in Mathematics Volume 1 Princeton University Press (1954) L.C. Card 53-6388 (A very accessible English translation of Euler's memoir regarding this "Most Extraordinary Law of the Numbers" appears starting on page 91)
  • {{Apostol IANT}} (Provides an introductory discussion of the Euler product in the context of classical number theory.)
  • G.H. Hardy and E.M. Wright, An introduction to the theory of numbers, 5th ed., Oxford (1979) {{isbn|0-19-853171-0}} (Chapter 17 gives further examples.)
  • George E. Andrews, Bruce C. Berndt, Ramanujan's Lost Notebook: Part I, Springer (2005), {{isbn|0-387-25529-X}}
  • G. Niklasch, ''Some number theoretical constants: 1000-digit values"

{{ref end}}